1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Semmy [17]
3 years ago
6

Given the following equation: Cu + 2 AgNO3 ---> Cu(NO3)2 + 2 Ag If 89.5 grams of Ag were produced, how many grams of Cu react

ed?
Chemistry
1 answer:
postnew [5]3 years ago
3 0

Answer:

mass of Cu = 26,34615g

Explanation:

The equation for reaction is

Cu + 2 AgNO3 ---> Cu(NO3)2 + 2 Ag

1mol       2mol            1mol           2mol

mass of Ag that reacted = 89.5g

molar mass of Ag =107.86h/mol

number of moles = mass/molar mass

number of moles of Ag = 89.5/107.86

                    =0.8298moles

from the stoichoimetric relation;

1mol of Cu reacted to produce 2moles of Ag;

hence 0.8298moles of Ag produce would require;  0.8298/2 moles of Cu to react

            =0.4149moles of Cu

mass of Cu = moles of Cu * molar mass of Cu

molar mass(Cu) = 63.5g

mass of Cu = 0.4149 * 63.5

mass of Cu = 26,34615g

You might be interested in
How to get the formulas for these compounds
Travka [436]
So what you’re going to do is basically the + and - in each top hand corner is the charge of compound, so for example Li has a charge of +1 while Br has a charge of -1 , to write the formula you need to get the charges to cancel out ( equal zero) so luckily this was easy because -1 +1 =0 ! So it would be LiBr. Though for another example Al has a charge of 3+ while br has a charge of -1 and these do not equal zero, so as a result you have to add more br making the Formula AlBr3! Hope this helps!
5 0
3 years ago
What types of elements- metals,
crimeas [40]

Answer:

Noble gases

Explanation:

The noble gases are non-metals that requires the highest amount of energy to remove an electron from their shells.

The reason for this difficult is that their electronic configuration confers a stable configuration them.

  • The ionization energy is the energy required to remove the most loosely held electrons in an atom.
  • Due to the special stability of noble gases, it is very difficult to remove electrons from an atom of noble gases.
7 0
3 years ago
If half of the moon is always illuminated why does its appearance from earth change?
irina [24]

Answer:

The different angles the moon has from sunlight to the earth

Explanation:

3 0
3 years ago
Read 2 more answers
HEELLPP PLEASE IM BEGGING ILL GIVE BRAINLIEST
Arisa [49]

Answer:

C

Explanation:

You mix different thing together to make a new thing.

6 0
3 years ago
The table shows the percentages of hydrocarbons that are found in a sample of crude oil. Hydrocarbons Percentage Paraffins 30 Na
ioda
This will be classified as light on the API scale due to the large percentage of lighter fractions such as paraffins and naphthenes. 
4 0
4 years ago
Read 2 more answers
Other questions:
  • Need help please!!!!!!!!
    7·1 answer
  • In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?
    5·1 answer
  • The dumping of wastewater from this pipe is an example of what type of pollution?
    13·1 answer
  • How are repetition and replication alike and different
    8·1 answer
  • Molecules stop moving once equilibrium is reached (true or false​
    6·1 answer
  • A) Calculate the standard free-energy change at 25 ∘C for the following reaction:
    12·1 answer
  • Which element burn with a characteristics of green flame<br>please cleet all that apply​
    11·1 answer
  • Two trays of lasagna are identical except for their thermal energies.
    11·2 answers
  • How to identify sodium hydroxide,hydrochloric acid,ans=d sugar solution when we only have blue litmus paper
    6·1 answer
  • 1. How many joules of heat are necessary to melt 500 g of ice at its freezing point?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!