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marissa [1.9K]
3 years ago
5

A solution of an acid could have a pH of __* 3 to 5 6 to 8 9 to 11 12 to 14

Chemistry
1 answer:
sdas [7]3 years ago
4 0

Answer:

3 to 5

Explanation:

The pH scale is from 0 to 14.

Acids have a pH of anything less than 7.

Anything with a pH greater than 7 is considered to be a base.

If a solution has a pH of 7, it is neutral.

3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.

6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.

9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.

Therefore, the correct answer is 3 to 5.

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1 year ago
0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati
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Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

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Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

                       

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