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4 years ago

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Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist h

er and parks their car 14 meters from the front of her car. Marcella grabs the car bumper and pulls very hard, with 200 N of force. The work she does transfers energy out, it reduces the K of the car, as it gradually approaches the other car. a) What is the initial kinetic energy before she tries to stop the car? b) What is the final kinetic energy, when her car hits the other car? What is the speed? c) Suppose the other person also slowed her car, pushing it from the front. How much force would be needed to stop her car 1 meter from the other car? [1 m allows the person not to be crushed!]

1 answer:

Nady [450]4 years ago

3 0

Answer:

Explanation:

a) KE = (1/2) * m * ( $v^{2}$ ) = F * d = 14m * 200N = 2800 m/N or 2.8 * $10^{3}$ m/N

b) 0J and 0m/s (if Marcella stopped after going 14 meters)

c) Known from part (a) that KE = 2800 J = F1 * d1,

2800J = F1 * (14m - 1m) => F1 = 2800J/13m = 215.384 N

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