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elixir [45]
2 years ago
5

Will give brainlist 20 points

Physics
2 answers:
Elina [12.6K]2 years ago
8 0

Answer:

I think its uniform I dont really know

Alex777 [14]2 years ago
3 0
I believe the answer is uniform please thank me
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The path that thermal energy follows is from ___________ to ___________
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Warmer to colder objects
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Which of the following is sometimes called electrical potential?
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C. Voltage.

Voltage is sometimes called electrical potential.
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Calculate the density of a 20 g object it is volume is 10cm3
zloy xaker [14]

Answer:

2000 kgm-3

Explanation:

Density = (Mass (kg))⁄(Volume (m3) )  

20 g = 20 ×(10)-3)kg

10 cm3 = 10 ×(10)(-6) m3

Density = (20 ×(10)(-3)) ⁄ (10 ×(10)(-6)  )

= 2000 kgm-3  

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3 years ago
Which characteristic is common to the four outer planets in our solar system?.
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2 years ago
Three identical metal spheres are hung from a ceiling on rigid non-conducting rods. Sphere 1, sphere 2, and sphere 3 have charge
Sloan [31]

Answer:

a) The net electric force on the middle sphere due to spheres 1 and 3 is 404N. b) The direction of the net electric force is to the left.

Explanation:

In order to solve this problem, we must first draw our free body diagram (See attached picture).

By definition, two opposite charges attract each other, so the force due to sphere 1 will go to the left (being the left direction negative) and the force due to sphere 3 will go to the right (being the right direction positive).

Knowing this we can use the electric force formula to calculate each of the forces:

F_{e}=k_{e}\frac{q_{1}q_{2} }{r^{2} }

where k_{e}=8.99x10^{9}N\frac{m^{2} }{C^{2} }

So knowing this, we can now calculate each force. Let's start with the force exerted by sphere 1 over sphere 2:

F_{12}=8.99x10^{9}N\frac{m^{2} }{C^{2} }\frac{(71x10^{-6}C)(52x10^{-6}C) }{(0.17m)^{2} }

Which gives me a force of:

F_{12}=-1148.48N

In this case the force will be negative because it's directed towards sphere 1, this is to the left.

We can do the same with the force due to sphere 3:

F_{23}=8.99x10^{9}N\frac{m^{2} }{C^{2} }\frac{(46x10^{-6}C)(52x10^{-6}C) }{(0.17m)^{2} }

Which gives me a force of:

F_{23}=744.09N

In this case the force is positive because it's directed towards sphere 3, this is it goes to the right.

With these two values I can now find the net force electric force on the middle sphere due to spheres 1 and 3.

F_{net}=∑F

F_{net}=F_{12}+F_{23}

F_{net}=-1148.48N+744.09N

F_{net}=-404.39N

a) Since part a of the problem only asks us for the magnitude, then the net electric force on the middle sphere due to spheres 1 and 3 is 404.39N

b) since the answer when solving this problem was negative, this means that the force will be directed towards sphere 1, this is to the left.

8 0
3 years ago
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