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Sloan [31]
3 years ago
7

You work 40 hours/week for 52 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e

arn the most? $17.00/hour and a $1,000 bonus at the end of the year $32,000/year with a 10% bonus $32,000/year $17.00/hour
Mathematics
1 answer:
Kay [80]3 years ago
8 0

Answer:

The best possible answer is A) $17.00 and hour with a $1,000 bonus.

Step-by-step explanation:

You can start by narrowing down the answers to the ones with the bonuses. The others are obviously less as it is the same pay without added bonus. Next we can determine the amount in answer A by multiplying the amount per hour by the number of hours in a week and by the number of weeks in a year.

$17.00 * 40 * 52 = $35,360

And then you add the $1,000 bonus.

Answer A Amount = $36,360

Now to find answer D amount, we multiply the total by the 10% bonus to find the bonus amount.

$32,000 * 10% = $3,200

Now we add that to the previous salary to get the overall D answer amount.

$32,000 + $3,200 = $35,200

As you can see, the amount in answer A is the larger amount.

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Answer:

n = -1

Step-by-step explanation:

you've accidently substracted 6n from 12n when you were supposed to be adding them. (-6n becomes +6n when brought to the otherside of the equal sign)

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Stacey earns $15 each week plus $.50 for each customer on her paper route.she wants to earn at least $25 each week. What equatio
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Read 2 more answers
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
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