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Sloan [31]
3 years ago
7

You work 40 hours/week for 52 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e

arn the most? $17.00/hour and a $1,000 bonus at the end of the year $32,000/year with a 10% bonus $32,000/year $17.00/hour
Mathematics
1 answer:
Kay [80]3 years ago
8 0

Answer:

The best possible answer is A) $17.00 and hour with a $1,000 bonus.

Step-by-step explanation:

You can start by narrowing down the answers to the ones with the bonuses. The others are obviously less as it is the same pay without added bonus. Next we can determine the amount in answer A by multiplying the amount per hour by the number of hours in a week and by the number of weeks in a year.

$17.00 * 40 * 52 = $35,360

And then you add the $1,000 bonus.

Answer A Amount = $36,360

Now to find answer D amount, we multiply the total by the 10% bonus to find the bonus amount.

$32,000 * 10% = $3,200

Now we add that to the previous salary to get the overall D answer amount.

$32,000 + $3,200 = $35,200

As you can see, the amount in answer A is the larger amount.

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Answer:

x = 19.6

Step-by-step explanation:

If we need to find the value of x then first we need to

(7x-25) + (3x +9) = 180  (angles at the same side of transversal will be equal to 180 degree )

10x -16 = 180

10x = 180 +16

10x = 196

x = 196/10

x = 19.6

4 0
3 years ago
What is the slope of a line perpendicular to the line with equation y = 1/6x – 2? help pls very urgent
valina [46]
Solution:

1) Simplify \frac{1}{6}x to \frac{x}{6}
y=\frac{x}{6}-2

2) Add 2 to both sides
y+2=\frac{x}{6}
​​
3) Multiply both sides by 6
(y+2)\times 6=x

4) Regroup terms
6(y+2)=x

5) Switch sides
x=6(y+2)

Done!
7 0
3 years ago
Help me please<br>help me please​
Nikolay [14]

Answer:

1 second

Step-by-step explanation:

s=-5\\u=0\\v=\\a=-10\\t=t

\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}

7 0
2 years ago
6. Fill in the smallest digit to make the number divisible by:
Degger [83]

Answer:

(i) 7164<u>0</u>, 32197<u>0</u>

(ii) 1<u>1</u>43, 47<u>2</u>05, <u>2</u>316

(iii) <u>1</u>428, 9<u>2</u>52, 721<u>2</u>

(iv) 2462<u>0</u>, 91<u>00</u>, 670<u>0</u>

(v) 1232<u>0</u>, 59<u>0</u>16, 4642<u>4</u>

Step-by-step explanation:

(i) In order for any number to be divisible by 5, its last digit must be <u>either 0 or 5</u>.

In this case, we should add a last digit, so we opt for <u>0</u> without any doubt since it gives a smaller number than <u>5</u> as the last digit: 71640 is smaller than 71645, the same way as 321970 is smaller than our second option, 321975.

(ii) If the sum of a number's digits gives a number divisible by 3, then the main number is also divisible by 3.

This means that we have to do some addition:

1_43: 1 + 4 + 3 = 8. Eight is not divisible by 3. But <u>9</u> is. So the smallest digit we can add for it to be divisible by three is <u>1</u>: <em>1143.</em>

47_05: 4 + 7 + 0 + 5 = 16. Since 16 is not, the next number that is divisible by 3 is 18, and therefore, the smallest digit we need here is <u>2</u>: <em>47205.</em>

_316: 3 + 1 + 6 = 10. Twelve is the next number divisible by 3, and that means <u>2</u> is the digit we choose: <em>2316.</em>

(iii) Only numbers that are divisible by both <u>2 and 3</u> are also divisible by 6.

_428: In order for a number to be divisible by 2, its last digit must be 0 or divisible by 2. That is already the case here.

4 + 2 + 8 = 14 which is not divisible by 3. But 15 is. So the smallest digit we need is <u>1</u>: <em>1428.</em>

9_52: The number will be divisible by 2. And 9 + 5 + 2 = 16 which is not divisible by 3 but 18 is. This means the smallest digit we need is <u>2</u>: <em>9252.</em>

721_: Since the last digit can be any of these <u>0, 2, 4, 6, 8</u> for the number to be divisible by two, we will first see what digit we need for it to be divisible by 3.

7 + 2 + 1 = 10 which is not divisible by 3 but 12 is. We will then choose to add <u>2</u>: <em>7212.</em>

(iv) A number is divisible by 4 only if the number that is formed by its two last digits is also divisible by 4..

2462_: Since we need to add a last digit, this should be easy. The smallest two-digit-number that starts with 2 and is divisible by four is <u>20</u>: <em>24620. </em>

91__: Here we need to add both of the two last digits, and this should be the easiest example! All numbers that end in <u>00</u>, meaning they have a round number of hundreds, are divisible by 4! Therefore our option is: <em>9100.</em>

670_: In this case, we apply the same rule from the last example - and we choose <u>0</u>: <em>6700.</em>

(v) In order for a number to be divisible by 8, its last three digits need to be divisible by 8, or it can end in <u>000,</u> since every number having a round number of thousands is also divisible by 8.

1232_: 320 is divisible by 8 since 8 × 40 gives 320. Therefore, our smallest digit here is <u>0</u>: <em>12320.</em>

59_16: If we add a <u>0</u> here, the last three digits form the number 016, which is divisible by 8. Our choice is again zero: <em>59016.</em>

4642_: Unfortunately, 420 is not divisible by 8. The next number closest to 420 and which is divisible by 8 is 424. Its division by 8 gives 53. Therefore we should add <u>4</u>: <em>46424.</em>

7 0
3 years ago
For each value of u, determine whether it is a solution to 6u-1&lt; −19. u Is it a solution? Yes or No 5 −4 −3 8
Agata [3.3K]

Answer:

No it is not a solution to 6u-1<-19

7 0
2 years ago
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