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2 years ago

Last time I'm asking this, answer, this time, 50 points.

Chemistry

1 answer:

EleoNora [17]2 years ago

6 0

Explanation:

Well i mean clothes so cells make tissues which help organs clothes can technically help you if you fall it has layers so it woulf be as a cell?

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Density is the _____ of a certain ______

olga2289 [7]

I think the first blank is "solidity" and second is "object."

3 0

3 years ago

Pls help me !!!! Is for chemistry

Sphinxa [80]

Answer:

Explanation:

1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L

2) Molar mass of NaCl is 23+35 = 58g

Molarity = (0.5/58)/0.075 = 0.115 Mol/L

3) Molar mass of $Li_{2}SO_{4}$ = 7x2 + 32 + 16x2 = 78g

Molarity = (734/78)/0.875 = 10.754 Mol/L

5) Molar mass of $Pb(C_{2}H_{3}O_{2})_{4}$

= 207.2 + ((12x2) + (1x3) + (16x2))x4

= 207.2 + (24+3+32)x4 = 443.2g

Molarity = (0.0672/443.2)/0.1335 = 0.001135 Mol/L

6) Both are the same.

Solution 1 Molarity = 1.0/1.0 = 1 Mol/L

Solution 2 Molarity = 1.0/1.0 = 1 Mol/L

Molarities of the solutions are the same.

7 0

3 years ago

3. Count the number of hydrogen atoms in 2 molecules of vitamin C (2c6H8O6

Alja [10]

There are 16 hydrogen atoms

3 0

2 years ago

What is a chemical formula, and what does it tell you?

katrin2010 [14]

Explanation:

chemical formula tells you the specific elements included in the compound and the number of atoms of each. The letters in a chemical formula are the symbols for the specific elements. So for example, H means hydrogen.

7 0

2 years ago

Read 2 more answers

Consider the following reaction, equilibrium concentrations, and equilibrium constant at

REY [17]

Answer:

Equilibrium concentration of $H_{2}O$ is 12.5 M

Explanation:

Given reaction: $C_{2}H_{4}+H_{2}O\rightleftharpoons C_{2}H_{5}OH$

Here, $K_{c}=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}][H_{2}O]}$

where $K_{c}$ represents equilibrium constant in terms of concentration and species inside third bracket represent equilibrium concentrations

Here, $[C_{2}H_{4}]=0.015M$ , $[C_{2}H_{5}OH]=1.69M$ and $K_{c}=9.0$

So, $[H_{2}O]=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}]\times K_{c}}=\frac{1.69}{0.015\times 9.0}=12.5M$

Hence equilibrium concentration of $H_{2}O$ is 12.5 M

5 0

3 years ago