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3 years ago

someone help me please haha Calculate the braking force of a lorry decelerating at a rate of 8 m/s² with a mass of 5000 kg.

Physics

1 answer:

ICE Princess25 [194]3 years ago

6 0

Answer:

40000 N

Explanation:

Force: This cam be defined as the product of mass and acceleration.

From the question,

The braking force of the lorry will be the same in magnitude as the force at which the lorry is moving.

F = ma..................... Equation 1

Where m = mass of the lorry, a = acceleration/deceleration of the lorry.

Given: m = 5000 kg, a = 8 m/s²

Substitute these values into equation 1

F = 5000(8)

F = 40000 N

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A pan hangs from a 50 cm spring. When a 10 kg mass is placed in the pan, it stretches the spring 6 cm. What is a function rule l

MrRissso [65]

Answer:

Explanation:

A Spring stretches / compresses when force is applied on them and they are governed by the Hookes Law which states that the force required to stretch or compress a spring is directly proportional to the distance it is stretched.

$F = -kx$

F is the force applied and x is the elongation of the spring

k is the spring constant.

negative sign indicates the change in direction from equilibrium position.

In the given question, we dont have force but we know that the pan is hanging. We also know from the Newton's second law of motion that

$F=mg$

Inserting this into Hooke's Law

$mg=-kx$

computing it for x,

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2 years ago

A person makes a cup of coffee by first placing a 200 W electric immersion heater in 0.32 kg

alexdok [17]

Answer:

Answer is D. 8.04 x 10^4 J

Explanation:

1. D

2. A

3. D

4. B

5. C

6. B

7. D

8. C

9. B

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8 0

2 years ago

The core of a 400 Hz aircraft transformer has a net cross-sectional area of 13 cm2. The maximum flux density is 0.9 T, and there

jenyasd209 [6]

Answer:

32.76 Volt

Explanation:

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According to the Faraday's law of electromagnetic induction, the induced emf is equal to the rate of change of magnetic flux.

e = dФ/dt

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2 years ago

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Rudik [331]

Answer:

W = 2352 J

Explanation:

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mass of the bucket, M = 10 kg

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height of the platform, h = 30 m

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rate of loss of water-mass, m = $0.4 kg.min^{-1}$

Here, according to the given situation the bucket moves at the rate,

$v=3 m.min^{-1}$

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$M=(10-0.4t) kg$

Consider the time interval between t and t + ∆t. During this time the bucket moves a distance

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<u>For work calculation:</u>

$W=\int_{0}^{10} [(10-0.4t).g\times 3] dt$

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3 years ago

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balu736 [363]

Answer:

Hindi ko po alam

Explanation:

Kaya sa iba ka nalang mag tanong kac Bobo ako jaan

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2 years ago