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navik [9.2K]
3 years ago
12

Every time there is a full moon, Mrs. Cook insists that students in her classes display strange behavior. What would be the best

way for her to prove the validity of her theory?
Physics
2 answers:
VikaD [51]3 years ago
7 0

Answer:

the answer is B

Explanation:

the guy above is saying B and i just took the test and its right.

have a good day

lidiya [134]3 years ago
4 0
Here is the answer to the question. Every time when there is a full moon, Mrs. Cook insists that students in her classes display strange behavior and the best way for her to prove the validity of her theory is to r<span>esearch data to find concrete evidence of a link between the moon cycle and human behavior. Hope this helps.</span>
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Discuss the correlation or connection between stars with a higher mass and the amount of fuel they have to work with
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Larger stars have a higher amount of fuel in order to keep the process of nuclear fusion going.
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One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i
Musya8 [376]

The annual production of carbon dioxide is 124121.49×10^{6}[/tex] kg.

First we calculate the fuel consumed by each car in a year

Fuel consumed=6990/21.4=326.63 gallon

Now we calculate the amount of fuel consumed by 40 million cars in a year

Fuel consumed=326.63*40*10^6=13065.42 million gallon,

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3 years ago
A 60-kg motor sits on four cylindrical rubber blocks. Each cylinder has a height of 3 cm and a cross-sectional area of 15 cm2. T
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3 years ago
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Answer:

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4 0
3 years ago
A bullet with a mass ????=12.5 g and speed ????=86.4 m/s is fired into a wooden block with ????=113 g which is initially at rest
skad [1K]

Answer:

a) 8.61 m/s, b) 5.73 m

Explanation:

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(12.5 g) (86.4 m/s) = (12.5 g + 113 g) V

V = 8.61 m/s

b) After the collision, energy is conserved.

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1/2 (m + M) V² = F d

1/2 (m + M) V² = N μk d

1/2 (m + M) V² = (m + M) g μk d

1/2 V² = g μk d

d = V² / (2g μk)

d = (8.61 m/s)² / (2 × 9.8 m/s² × 0.659)

d = 5.73 m

Notice we used the kinetic coefficient of friction.  That's the friction when an object is moving.  The static coefficient of friction is the friction on a stationary object.  Since the bullet/block combination is sliding across the surface, we use the kinetic coefficient.

4 0
3 years ago
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