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navik [9.2K]
3 years ago
12

Every time there is a full moon, Mrs. Cook insists that students in her classes display strange behavior. What would be the best

way for her to prove the validity of her theory?
Physics
2 answers:
VikaD [51]3 years ago
7 0

Answer:

the answer is B

Explanation:

the guy above is saying B and i just took the test and its right.

have a good day

lidiya [134]3 years ago
4 0
Here is the answer to the question. Every time when there is a full moon, Mrs. Cook insists that students in her classes display strange behavior and the best way for her to prove the validity of her theory is to r<span>esearch data to find concrete evidence of a link between the moon cycle and human behavior. Hope this helps.</span>
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Please help on this one?
dezoksy [38]

the answer is heat engine

3 0
4 years ago
What is the thermal energy of an object?
Vedmedyk [2.9K]
The total kinetic and potential energies
3 0
3 years ago
Under ideal conditions (no atmospheric interference of any kind), if I hit a golf ball at an angle of 25 degrees at an initial s
g100num [7]

Answer:

The required angle is (90-25)° = 65°

Explanation:

The given motion is an example of projectile motion.

Let 'v' be the initial velocity and '∅' be the angle of projection.

Let 't' be the time taken for complete motion.

Let 'g' be the acceleration due to gravity

Taking components of velocity in horizontal(x) and vertical(y) direction.

v_{x} =  v cos(∅)

v_{y} =  v sin(∅)

We know that for a projectile motion,

t =\frac{2vsin(∅)}{g}

Since there is no force acting on the golf ball in horizonal direction.

Total distance(d) covered in horizontal direction is -

d = v_{x}×t = vcos(∅)×\frac{2vsin(∅)}{g} = \frac{v^{2}sin(2∅) }{g}.

If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -

α +β = 90° as-

d = \frac{v^{2}sin(2α) }{g} = \frac{v^{2}sin(2[90-β]) }{g} =\frac{v^{2}sin(180-2β) }{g} = \frac{v^{2}sin(2β) }{g} .

∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.

∴ If α = 25° , then

     β = 90-25 = 65°

∴ The required angle is 65°.

5 0
3 years ago
Read 2 more answers
Some good estimates about the human body can be made if it is assumed that we are made mostly of water. The mass of a water mole
Bezzdna [24]

Answer:

Explanation:

Given

mass of water molecule m=2.99\times 10^{-26}\ kg

mass of person M=62\ kg

It is given that body is mostly made up of water

suppose n water molecules constitutes 62 kg

so n\times m=M

n=\frac{62}{2.99\times 10^{-26}}

n=20.73\times 10^{26}\ kg

6 0
3 years ago
The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
Ksenya-84 [330]

Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

                     = 0.02 x (180/\frac{22}{7})

0.02 radians  = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

So that,

Tan 1.146° = \frac{h}{10500}

⇒ h = Tan 1.146° x 10500

      = 2.21074 x 10500

      = 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

8 0
3 years ago
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