Given parameters:
First velocity = 2.50m/s
Time of travel = 3s
Second velocity = 1.50m/s
Unknown:
The displacement during the first interval = ?
Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.
Velocity = 
So;
Displacement = Velocity x Time taken
Now input the parameter for the first velocity and time of travel;
Displacement = 2.5 x 3 = 7.5m
The displacement id 7.5m
Answer:
If the force remains the same, the acceleration would decrease
Explanation:
According to Newton's second law, the acceleration of an object is given by

where
F is the force applied to the object
m is the mass of the object
As we see from the formula, the acceleration a is inversely proportional to the mass, m. Therefore, if the force F remains constant, this means that if the mass of the skateboarder increases, then the acceleration will decrease.
<u>Answer:</u>
The ball fall vertically 2.69 ft by the time it reached home plate 60.0 ft away.
<u>Explanation:</u>
Fastest recorded pitches major-league baseball, thrown by nolan ryan in 1974 = 100.8 mi/hr = 44.8 m/s
The horizontal distance to home plate = 60.0 ft = 18.288 m
We have the horizontal velocity = 44.8 m/s
So time taken = 18.288/44.8 = 0.408 seconds.
The distance traveled by baseball vertically is found out by equation 
Here u =0m/s, a = 9.81
and t = 0.408 s
Substituting

So vertical distance traveled = 0.82 m = 2.69 ft
If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.
Answer: Option B
<u>Explanation:</u>
A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.
Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.