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slamgirl [31]
3 years ago
13

PY85

Physics
1 answer:
aliya0001 [1]3 years ago
3 0

Answer:

460 g

Explanation:

Heat lost by the warm water = heat gained by the cold water

-mCΔT = mCΔT

-m (4.184 J/g/K) (37°C − 85°C) = (1000 g) (4.184 J/g/K) (37°C − 15°C)

-m (37°C − 85°C) = (1000 g) (37°C − 15°C)

-m (-48°C) = (1000 g) (22°C)

m = 458 g

Rounded to two significant figures, you need a mass of 460 g of water.

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In an RL series circuit, an inductor of 3.54 H and a resistor of 7.76 Ω are connected to a 26.6 V battery. The switch of the cir
podryga [215]

Answer:

Energy stored in inductor will be 20.797 J

Explanation:

We have given inductance L = 3.54 H

And resistance R = 7.76 ohm

Battery voltage V = 26.6 VOLT

After very long time means at steady state inductor behaves as short circuit

So  current i=\frac{V}{R}=\frac{26.6}{7.76}=3.427Amp

Now energy stored in inductor E=\frac{1}{2}Li^2=\frac{1}{2}\times 3.54\times 3.427^2=20.797J

So energy stored in inductor will be 20.797 J

4 0
4 years ago
A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the
MArishka [77]

Answer:

The  the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is  

   I_c = \frac{I}{I_o}  =8.48 *10^{-8}

Explanation:

From the question we are told that

   The  width of the slit is  D  =  0.3 \ mm =  0.3 *10^{-3} \ m

    The  wavelength is  \lambda =  254 \ nm =  254 *10^{-9} \ m

     The angle is  \theta  =  11^o

The intensity of at 11^o to the axis in terms of the intensity of the central maximum. is mathematically represented as

        I_c = \frac{I}{I_o}  = [ \frac{sin \beta  }{\beta }] ^2

Where \beta is mathematically represented as

        \beta  =  \frac{D sin (\theta ) *  \pi}{\lambda }

substituting values

      \beta  =  \frac{0.3 *10^{-3} sin (11 ) * 3.142}{254 *10^{-9} }

     \beta  =  708.1 \ rad

So

  I_c = \frac{I}{I_o}  = [ \frac{sin (708.1)  }{(708.1)}] ^2

   I_c = \frac{I}{I_o}  =8.48 *10^{-8}

6 0
4 years ago
An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq
Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, f_2 = 1227 Hz

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

f_2=\dfrac{3v}{2l}

v is speed of sound

Let f is the fundamental frequency. It is given by :

f=\dfrac{v}{2l}

The relation between f and f₂ can be written as :

f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz

So, the fundamental frequency of the pipe is 409 Hz.              

6 0
3 years ago
If you follow a line through the "pointer stars" (the two stars in the bowl of the Big Dipper farthest from the handle) away fro
statuscvo [17]

Answer:

A) Polaris, the North star

Explanation:

Polaris, also known as the Pole star or north star, lies almost along the axis of Earth. Because of this Polaris seems to be fixed at one point in the sky while all other celestial objects change their positions in the sky due to rotation of Earth.

Since, it is fixed at one point in the sky in the North direction, explorers used to take help of Polaris to find direction in the night time. Since Polaris is not the brightest star in the night sky (it is 48th brightest star) our ancestors took help of constellations to find it. One of the method was to use Big Dipper of "Ursa Major" constellation. The pointer stars (Merak and Dubhe) of big dipper point towards the Polaris. One can easily spot it in the sky as well.

5 0
3 years ago
Suppose you increase your walking speed from 5 m/s to 15 m/s in a period of 1 s. What is your acceleration?
Novay_Z [31]
Using the kinematics equation vf = vi + at we plug in all known values 15 = 5 + a*1 solving for a we get 10m/s^2
4 0
3 years ago
Read 2 more answers
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