Answer:
Distance, S = 440 meters.
Explanation:
Given the following data;
Initial velocity, u = 17m/s
Time, t = 20 seconds
Final velocity, v = 27m/s
To find the distance;
First of all, we would determine the acceleration of the truck.
Acceleration = (v-u)/t
Substituting the given values into the equation, we have;
Acceleration = (27 - 17)/20
Acceleration = 10/20
Acceleration = 0.5m/s²
Now, we would use the second equation of motion to find the distance traveled.
S = ut + ½at²
S = 17*20 + ½*0.5*20²
S = 340 + 0.25*400
S = 340 + 100
S = 440m
<u>We are given:</u>
2 Vectors A and B
A = î - 5j
B = 2î - 10j
<u>Proving that the given vectors are Parallel:</u>
We can rewrite the Vector B as: B = 2(î - 5j)
Since A = î - 5j
Vector B can be written as:
B = 2(A vector)
this means that the magnitude of Vector B is twice of vector A but their direction is the same
Since the 2 vectors are moving in the same direction, they are parallel
The pressure at the depth h in the ocean is given by (Stevin's law)
where
is the atmospheric pressure
and
is the pressure exerted by the column of water of height h=4267 m, with
being the water density and
.
Substituting, we find
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so
, therefore we just need to divide by this number:
As per the given question,
Focal length of the concave mirror(f)=0.25m
position of virtual image form the mirror (v)=0.04m
let the position of the object from the concave mirror (u)=?
u=3.44cm