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Alexandra [31]
2 years ago
6

A man pushes a lawn mower with a force of 25 newtons. The lawn mower has a mass of 17 kilograms and the handle makes an angle of

60 degrees with the horizontal. How much work is done if the lawn mower is pushed a total of 500 meters
Physics
1 answer:
astra-53 [7]2 years ago
3 0

Answer:

6250 J

Explanation:

Work is the distance times the component of the force along that distance.

The horizontal component of the force is:

25 N × cos(60°) = 12.5 N

So the work done is:

W = (500 m) (12.5 N)

W = 6250 J

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Answer:

Option c. Inter-rater Reliability

Explanation:

Here, the rating is done by a group of data collectors under training for evaluation children's pain on Faces scale which is a scale ranging from 0 to 10 with different expressions or faces with a happy face at 0 to a crying face at 10.

Also in Inter-rater Reliability, the relative consistency of a study or test is assessed and the extent to which different group members rated the same behavior, the consistency of which is evaluated.

Thus it can also be helpful in interviews, etc.

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3 years ago
tom and ted are sitting on seprate chairs that have wheels. tom pushes ted and, in turn, he starts moving too. in which directio
IceJOKER [234]
In the direction opposite to his push.
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3 years ago
Which type of reaction happens when a base is mixed with an acid?
4vir4ik [10]

Answer:

Neutralization Reaction

6 0
3 years ago
Read 2 more answers
If a horse does 4000 J of work over 20 m, how much force does the horse use?
astraxan [27]
In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. It is calculated by the formula W = f x d. Therefore, we calculate the problem above as follows:

W = f x d
4000 = f x 20
f = 200 N <----- FIRST OPTION</span>
5 0
3 years ago
An electric motor exerts a constant torque of 10 Nm on a grindstone mounted on its shaft. The moment of inertia of the grindston
Dmitry_Shevchenko [17]

Answer:

Angular acceleration = 5 rad /s ^2

Kinetic energy = 0.391 J

Work done = 0.391 J

P =6.25 W

Explanation:

The torque is given as moment of inertia × angular acceleration

angular acceleration = torque/ moment of inertia

= 10/2= 5 rad/ s^2

The kinetic energy is = 1/2 Iw^2

w = angular acceleration/time

=5/8= 0.625 rad /s

1/2 × 2× 0.625^2

=0.391 J

The work done is equal to the kinetic energy of the motor at this time

W= 0.391 J

The average power is = torque × angular speed

= 10× 0.625

P = 6.25 W

6 0
3 years ago
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