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Anni [7]
3 years ago
13

If 5.58 g of iron reacts with sulfur to produce 8.79 g of iron sulfide, what is the mass of reacting sulfur? A) 3215 B) 14:37 C)

8.798 D) 5.58 g E) impossible to predict from the given information
Chemistry
1 answer:
gogolik [260]3 years ago
7 0

Answer: A) 3.21 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

Fe+S\rightarrow FeS

We are given:

Mass of iron = 5.58 g

Mass of iron sulphide = 8.79 g

Mass of sulphur = x g

Total mass on reactant side = 5.58 + x

Total mass on product side = 8.79 g

Applying law of conservation of mass, we get:

5.58+x=8.79\\\\x=3.21g

Hence, the mass of reacting sulfur is 3.21 g.

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worty [1.4K]

Answer:

29260J

Explanation:

Given parameters:

Mass of water sample  = 100g

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Unknown:

Energy required for the temperature change = ?

Solution:

The amount of heat required for this temperature change can be derived from the expression below;

     H  = m c (ΔT)

H is the amount of heat energy

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Now insert the parameters and solve;

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3 years ago
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The given balanced reaction is,

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The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

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Answer:

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Explanation:

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