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Tom [10]
3 years ago
12

A mixture is always made up of a combination of elements

Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
3 0
Yeah, it's diffferen than a solution.

What would it be if it were all the same element?
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In the reaction 4AI+_O2 2AI2O3, what coefficient should be placed in front of the O2 to balance the reaction?
Olegator [25]

Answer: 3

Explanation: I took the k12 quiz

3 0
3 years ago
What is the molarity of solution prepared by dissolving 11.75 g of KNO3 in enough water to produce 2.00 L of solution?
zysi [14]
The molar mass of the compound potassium nitrate, KNO3 is equal to 101.1032 g/mol. Then, we determine the number of moles present in the given amount,
                       n = 11.75g / (101.1032 g/mol) = 0.116 mol
Then, molarity is calculated by dividing the number of moles by the volume of the solution. The answer is therefore 0.058 M. 
3 0
3 years ago
Chemical or physical properties? titanium is less dense than water
Leya [2.2K]
Physical......................................................
5 0
3 years ago
Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

3 0
3 years ago
X2o3 express you answer as a whole number
kobusy [5.1K]
 <span>2.40 - 1.68 =0.72 g of oxigen 
moles = 0.72/16 g/mol=0.045 

moles x = 1.68/ 55.9=0.03 

0.03/0.03 = 1 = x 
0.045 / 0.03 = 1.5 = O 

to get whole numbers multiply by 2 

x2O3 

X2O3 +3 CO = 2 X + 3 CO2</span>
4 0
3 years ago
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