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Aleksandr-060686 [28]
3 years ago
13

A particular op amp using ±15-V supplies operates linearly for outputs in the range−14 V to+14 V. If used in an inverting amplif

ier configuration of gain −100,what is the rms value of the largest possible sine wave that can be applied at the input without output clipping?
Engineering
1 answer:
aniked [119]3 years ago
6 0

Answer:

V(rms) = 98.99 mV ≅ 100 mV

Explanation:

Outputs = -14 to +14

Gain = =100

We know that Gain = Output/Input

so, to find out the input voltage:

Input = Output/Gain

         = ±14/-100

Input = 0.14 V

This is the peak input voltage (Vpk) of the sine wave and the question is asking us to find the rms value.

To calculate the rms value:

V(rms) = V(pk)/√2

           = 0.14/√2

          = 0.09899

          = 98.99 mV

V(rms) ≅ 100 mV

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The steel bracket is used to connect the ends of two cables. if the allowable normal stress for the steel is sallow = 30 ksi, de
garri49 [273]

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

<h3>The static equilibrium is given as:</h3>

F = P (Normal force)

Formula for moment at section

M = P(4 + 1.5/2)

= 4.75p

Solve for the cross sectional area

Area = \frac{\pi d^{2} }{4}

d = 1.5

\frac{\pi *1.5^{2} }{4}

= 1.767 inches²

<h3>Solve for inertia</h3>

\frac{\pi *0.75^4}{4}

= 0.2485inches⁴

Solve for the tensile force from here

\frac{F}{A} +\frac{Mc}{I}

30x10³ = \frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\

30000 = 14.902 p

divide through by 14.902

2013.15 = P

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

Read more on tensile force here: brainly.com/question/25748369

4 0
2 years ago
Analyzing Manufacturing Production Process Development Tasks
artcher [175]

Answer:

4, 5, 6

Explanation:

i just did it

5 0
3 years ago
Read 2 more answers
A hypothetical metal has an orthorhombic unit cell for which the a, b, and c lattice parameters are 0.413 nm, 0.665 nm, and 0.87
Inessa [10]

Answer:

atomic radius  R = 0.157 nm

metal atomic weight = 72.27 g/mol

Explanation:

given data

parameters a =  0.413 nm

parameters b = 0.665 nm

parameters c =  0.876 nm

atomic packing factor = 0.536

density = 3.99 g/cm³

to find out

atomic radius and  atomic weight

solution

we apply  here atomic packing factor (x) that is

atomic packing factor (x) = \frac{volume(sphere)}{volume(unit\ cell)}  ..................1

put here value we get

atomic packing factor = \frac{8*(4/3)*\pi R^3}{3*a*b*c}

R = (\frac{3(x)(abc)}{32\pi })^{1/3}

R =  (\frac{3(0.536)(0.413*0.665*0.876)}{32\pi })^{1/3}

atomic radius  R = 0.157 nm

and

now we get here metal atomic weight that is

metal atomic weight = \frac{\rho (abc)(N_A)}{no\ of\ atom}   ....................2

metal atomic weight = \frac{3.99 (0.413*0.665*0.876)(6.023*10^{23})}{8}  

metal atomic weight = 72.27 g/mol

6 0
3 years ago
Some extremely hazardous materials used in welding operations include
Charra [1.4K]

Answer:

(Have a nice day)

¶Emma Jess¶

Explanation:

Extremly toxic substances;

£Chrimium

£ Nickel

£ Aresenic

£ Asbestose

£ Magnesium

£ Sillica

£ Beryllium

£ Cadmium

£ Nitrogen

£ Oxides

£ Phosgene

£ Acrolein

£ Carbon monoxide

£ Fluorine compounds

£ Cobalt

£ Copper

£ Lead

£ Ozon

£ Selenium

£ Zinc

8 0
3 years ago
How to find magnitude of net electric charge when current flows through a capacitor with initial charge?
Ksenya-84 [330]

Answer:

Q=qe^{-t/RC}

also

q=it

Explanation:

How to find magnitude of net electric charge when current flows through a capacitor with initial charge?

A capacitor is a device used in storing electric charges. The unit of capacitance is measured in farad

To find the magnitude of net electric charge in a capacitor, we use the following relation

Q=qe^{-t/RC}

Q=the magnitude of net electric charge in coulombs

t=the time for an electron tpo pass through the capacitor

R=the resistance of the capacitor , measured in ohms

C=the capacitance of the capacitor measures in Farad

q=initial quantity of charge

Having all the parameters above will make it possible to determine the net electric charge

Recall also that

q=it

quantity (coulombs)=current*time(s)

3 0
3 years ago
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