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SVETLANKA909090 [29]

4 years ago

5

Consider unsteady fully developed Coutte flow between two infinite parallel plates. This problem involves the following paramete

rs such as velocity component u, distance between the plates h, vertical distance y, top plate speed V, fluid density rho , fluid viscosity mu , and time t .
The number of expected dimensionless parameters pi subscript s of this problem is:

a. 6

b. 5

c. 4

d. 3

e. 2

1 answer:

FrozenT [24]4 years ago

6 0

Answer:

Option (C) = 4 is correct.

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

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VladimirAG [237]

I think it’s c but I’m not sure

8 0

4 years ago

Production of pressure vessels is fastening an open-ended cylinder and two rigid plates with bolts. The cylinder made of brass.

marysya [2.9K]

Answer:

The pressure that the container will start to leak is 154.87 psi

Explanation:

Force on end plates F = p(πR²) ⇒ pπR²

There is an equal reaction from four bolts ∴ F = pπR² / 4 .............. (1)

due to force on bolt, each bolt stretch by $\sigma_b$

Therefore; $\sigma_b = \frac{F_bL}{A_bE_b}$ .........................(2)

Leaking will start when tightening is outstretched by half turn per 16 turns per inch.

Cylinder experience a radial expansion as p increases. it is accompanied by poisson contraction $\sigma_c$ in axial direction. That is, the bolt do not have to experience a long stretch before the pressure breaks off the plate.

$\sigma_b + \sigma_c = \frac{1}{2} *\frac{1}{16} = \frac{1}{32}$ ...................... (3)

Axial deformation $\sigma_c$ of cylinder = L times axial ∈₀

<em>see continuation in attached picture in writing to get the value of Pressure: since we have the value of P</em>

R=8", L=16", t=0.125"

Area of bolts $A_b = \frac{\pi}{4}(\frac{7}{16})^2 = 0.150 inch^2$

$E_c = E_{cylinder} = 125$

$E_b = E_{bolt} = 200$

V for brass = 0.3

$P = \frac{1}{8*8*16} [\frac{0.150*12.5*200*0.125*10^9}{\pi*8*125*0.125+4*0.3*0.150*200}]$

p = 1.67797.183 P ⇒ 154.87 psi

7 0

4 years ago

A metal with a BCC structure, such as iron, usually exhibits which mechanical property?

elena-s [515]

Answer:

C can i have brainliest pleaseee

Explanation:

6 0

3 years ago

Do you know the compression ratio of your car? Is there any limit to an Otto cycle? Why?

galben [10]

Explanation:

Compression ratio:

Compression ratio is the ratio of volume .Generally it is denoted by r.From the diagram we can say that the compression ratio r

$r=\dfrac{V_1}{V_2}$

Generally compression ratio varies from 10 to 14 in petrol engine but on the other hand the compression ratio in diesel engine is more as compare to petrol .In diesel engine the compression ratio varies from 15 to 20.

Yes there is limit of compression ratio in Otto cycle.If compression ratio is high in Otto cycle then there will be more possibility of pre ignition of air fuel and this is called miss firing.This is not good for Otto cycle.

6 0

3 years ago

Steam enters an adiabatic nozzle at 2.5 MPa and 450oC with a velocity of 55 m/s and exits at 1 MPa and 390 m/s. If the nozzle ha

luda_lava [24]

Answer:

The value of exit temperature from the nozzle = 719.02 K

Explanation:

Temperature at inlet $T_{1}$ = 450°c = 723 K

Velocity at inlet $V_{1}$ = 55 $\frac{m}{sec}$

velocity at outlet $V_{2}$ = 390 $\frac{m}{sec}$

Specific heat at constant pressure for steam $C_{p} = 18723 \frac{J}{kg k}$

Apply steady flow energy equation for the nozzle

$h_{1} + \frac{V_{1} ^{2} }{2} = h_{2} + \frac{V_{2} ^{2} }{2}$

$C_{p} T_{1} + \frac{V_{1} ^{2} }{2} = C_{p} T_{2} + \frac{V_{2} ^{2} }{2}$

Put all the values in the above formula we get,

⇒ 18723 × 723 + $\frac{55^{2} }{2}$ = $C_{p}$ $T_{2}$ + $\frac{390^{2} }{2}$

⇒ $T_{2}$ = 719.02 K

This is the value of exit temperature from the nozzle.

4 0

4 years ago