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Dmitry [639]
3 years ago
5

If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

Chemistry
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l                             Volume 2 = ?

Temperature 1 = T1 = 479°K                   Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa                      Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

                P1V1/T1 = P2V2/t2

-Solve for V2

               V2 = P1V1T2 / T1P2

2.- Substitution

                V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

                V2 = 21096000 / 48534.675

4.- Result

                V2 = 434.7 l

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Airida [17]

Answer:

Ksp=2.00x10^{-8}

Explanation:

Hello!

In this case, since the pH of the given metal is 10.15, we can compute the pOH as shown below:

pOH=14-pH=14-10.15=3.85

Now, we compute the concentration of hydroxyl ions in solution:

[OH^-]=10^{-pOH}=10^{-3.95}=1.41x10^{-4}M

Now, since this hydroxide has the form MOH, we infer the concentration of OH- equals the concentration of M^+ at equilibrium, assuming the following ionization reaction:

MOH(s)\rightarrow M^+(aq)+OH^-(aq)

Whose equilibrium expression is:

Ksp=[M^+][OH^-]

Therefore, the Ksp for the saturated solution turns out:

Ksp=1.41x10^{-4}*1.41x10^{-4}\\\\Ksp=2.00x10^{-8}

Best regards!

4 0
2 years ago
What is 1.23 x 10^-3 in standard notation
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Answer:

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Explanation:

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6 0
3 years ago
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Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you
oee [108]

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

\eta_{KClO_{3}} = \frac{m}{M}

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

\eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles                                      

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

\eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles

Finally, the mass of O₂ is:

m = 0.378 moles*32 g/mol = 12.10 g

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

6 0
3 years ago
How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?
natka813 [3]

A would be correct have a nice day.


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