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3 years ago

If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

Chemistry

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l Volume 2 = ?

Temperature 1 = T1 = 479°K Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

P1V1/T1 = P2V2/t2

-Solve for V2

V2 = P1V1T2 / T1P2

2.- Substitution

V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

V2 = 21096000 / 48534.675

4.- Result

V2 = 434.7 l

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3 years ago

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

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Answer:

A) Sample B has more calcium carbonate molecules

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$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

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The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

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Hope it helps!
#MissionExam001

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4 years ago