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2 years ago

QUICK!! WILL MARK BRAINLIEST!! what is the volume of 2.7 moles of co2 ?

Chemistry

1 answer:

Kay [80]2 years ago

3 0

Answer:

60. L CO₂

Explanation:

Step 1: Define

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm

Step 2: Use Dimensional Analysis (Assuming we are dealing with STP)

$2.7 \hspace{3} mol \hspace{3} CO_2(\frac{22.4 \hspace{3} L \hspace{3} CO_2}{1 \hspace{3} mol \hspace{3} CO_2} )$ = 60.48 L CO₂

Step 3: Simplify

We are given 2 sig figs.

60.48 L CO₂ ≈ 60. L CO₂

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2 years ago

How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of 2.50x102 grams.

Elis [28]

One way of expressing concentration is by percent. It may be on the basis of mass, mole or volume. Percent is expressed as the amount of solute per amount of the solution. For this case, we are given the percent by mass. In order to solve the amount of solute, we multiply the percent with the amount of the solution.

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2 years ago

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san4es73 [151]

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2 years ago

Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and

Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%$

Then,

$Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%$

$Percent\ yield\ of\ copper\ hydroxide= 84\%$

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

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2 years ago

What generic products are produced by an Acid/Base reaction?

gavmur [86]

Answer:

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Explanation:

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2 years ago