Answer:
Periods have consecutive atomic number as they are in a row and groups are vertical meaning they are in a column and groups have similar properties
5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
Given that <span>sample a has a higher melting point than sample
b. Therefore, sample a is a longer chain of a </span><span>fatlike solid substance. It could also be that the bonds present in sample a is much stronger which will require more energy to break. Hope this answers the question.</span>
Answer:
B. oxygen and glucose
Explanation:
Oxygen for respiration and glucose for energy utilization
Answer:
C.) At room temperature and pressure, because intermolecular interactions are minimized and the particles are relatively far apart.
Explanation:
For gas to behave as an ideal gas there are 2 basic assumptions:
- The intermolecular forces (IMF) are neglectable.
- The volume of the gas is neglectable in comparison with the volume of the container.
<em>In which instance is a gas most likely to behave as an ideal gas?</em>
<em>A.) At low temperatures, because the molecules are always far apart.</em> FALSE. At low temperatures, molecules are closer and IMF are more appreciable.
<em>B.) When the molecules are highly polar, because IMF are more likely.</em> FALSE. When IMF are stronger the gas does not behave as an ideal gas.
<em>C.) At room temperature and pressure, because intermolecular interactions are minimized and the particles are relatively far apart.</em> TRUE.
<em>D.) At high pressures, because the distance between molecules is likely to be small in relation to the size of the molecules.</em> FALSE. At high pressures, the distance between molecules is small and IMF are strong.
