Answer:
Car A has twice the energy of car B.
Explanation:
The kinetic energy of an object is given by :

Where
m is the mass
v is the speed of the object
Car A has twice the mass of Car B. Both travel at the same speed i.e.

So,

So, the kinetic energy of car A is twice of the kinetic energy of car B.
Since 1 examiner = 10^18miner
then 10^10miners =10^(10-18)=10^-8examiner
Answer:
Option A
Explanation:
Velocity is expressed as distance covered per unit time, with respect to direction. Therefore, v=d/t
Given distance west as 60 km and time as 1.33 then velocity will be
V=60/1.33=45.112781954887 km/h
Rounded off as 45.11 km/h West
Velocity in East will also be given by substituting 40 km for d and 0.67 h for h hence
V=40/0.67=59.701492537313 km/h rounded off as 59.70 km/h East
Taking East as positive then West as negative, the sum of two velocities will be (59.70+-45.11)/2=7.295 km/h East
Approximately 10 km/h East since it is positive
Complete question:
The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass of 15.0 kg. When the gun fires a projectile with a mass of 0.040 kg and a speed of 380 m/s, what is the recoil velocity of the shotgun and arm–shoulder combination?
Answer:
The recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
Explanation:
Given;
combined mass of the shotgun and arm–shoulder, m₁ = 15 kg
mass of the projectile, m₂ = 0.04 kg
speed of the projectile, u₂ = 380 m/s
let the recoil velocity of the shotgun and arm–shoulder combination = u₁
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = 0
m₁u₁ = - m₂u₂

Therefore, the recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
15 because i did the math, had this assignment, and also watch a video