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Elenna [48]
3 years ago
12

What equation illustrates the law of conservation of matter?

Physics
1 answer:
scoray [572]3 years ago
3 0
 <span>In a correctly balanced chemical equation, there are exactly the same number of atoms for each element found on both side of the equation (that is, in the reactants and the products). 

No new atoms were made. None were destroyed. Matter was conserved.</span>
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How is the pressure of a gas related to its concentration of particles?A) Pressure will expand a gas, enlarging its volume and r
Lesechka [4]

Answer:

C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.

Explanation:

At constant temperature, pressure and volume are inversely related.

P V = constant

\Rightarrow P \propto \frac{1}{V}

As the pressure increases, the gas compresses, the particles come closer reducing the volume of gas.

As we know, with decrease in volume, density increases.

Density = \frac{Mass}{Volume}

Density \propto \frac{1}{Volume}

Thus, the pressure of a gas is directly related to concentration of particles. Increase in pressure causes increase in concentration of the particles.

8 0
3 years ago
Describe where metals and nonmetals are found on the periodic table
Studentka2010 [4]

Non metals are all the way on the right side

Metalloids are the stair case

Metals are on the left side

4 0
4 years ago
A sinusoidal, transverse wave that propagates in the positive x-direction can be described with the wave function y of xt is equ
myrzilka [38]

Answer:

\omega =\frac{2 \pi }{T} rad/s

Explanation:

The wave function is:

y(xt) = Acos(kx- \omega t)

where :

k = wave number

x = position of a point on the wave

\omega = angular frequency

t = time

What is another way to express the angular frequency (omega)

Angular frequency (omega) can be express as :

\omega =\frac{2 \pi }{T} rad/s ( i.e one repetition that it takes to repeats itself)

4 0
3 years ago
You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice
Galina-37 [17]

The stopping distance is 143.1 m

Explanation:

First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:

\sum F =ma

where

\sum F = F_f = -0.14 N is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)

m = 0.12 kg is the mass of the puck

a is the acceleration

Solving for a,

a=\frac{\sum F}{m}=\frac{-0.14}{0.12}=-1.17 m/s^2

The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2-u^2=2as

where:

v = 0 is the final velocity (the puck comes to a stop)

u = 18.3 m/s is the initial velocity

a=-1.17 m/s^2 is the acceleration

s is the stopping distance

And solving for s, we find

s=\frac{v^2-u^2}{2a}=\frac{0-(18.3)^2}{2(-1.17)}=143.1 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
3 years ago
What is the relationshop between a pure substance and a mixture
ryzh [129]

The difference between a pure substance and a mixture is that mixtures are combinations of two or more pure substances, while pure substances cannot be separated into any other kinds of matter.

7 0
3 years ago
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