Answer:
5.00
Explanation:
a sinθ=mλ
You are missing (a) so you move sinθ to the other side than solve from there.
Answer:
A.
Explanation:
To solve this problem it is necessary to take into account the concepts related to angular velocity and centripetal acceleration,
from the cinematic equations of motion we know that
where,
V = Tangential Velocity
r = radius
Angular velocity
While the centripetal acceleration is given by
The displacement of the object is based on gravitational acceleration, so
a = g = 9.8 and the radius would be
Reemplazando:
Therefore the answer is A.
Answer:
For mass m 1 newton 2nd law
F=m 1 a 1
5=m 1 ×10
m 1 = 2
1
kg
For mass m 2
F=m 2 a 2
5=m 2
×20
m 2
= 4
1 kg
if tied together
Total mass =m 1 +m 2 = 1/2 +1/4=3/4kg
Now
F=M
T Q
T
a T = 5/m T = 5×4/3 = 3
/20m/s^2
Explanation:
Answer:
F = 30 N Directed up
Explanation:
We can solve this problem using the momentum and momentum relationship.
I = ΔP
I = ∫ F dt
As we are asked for the average force, that leaves the integral, giving
I = F t
F t = m - m v₀
F = m (-v₀) / t
Note that, if you define the upward positive direction, the initial velocity is negative
Let's calculate
F = 0.15 (3.5 - (-6.5)) / 0.050
F = 30 N
Directed up
Answer:
6 s
Explanation:
First of all, we calculate the acceleration of the car in the initial situation, using the equation
where
v = 30 is the final velocity of the car
u = 0 is the initial velocity
t = 12 s is the time taken
Substituting,
So, this is the acceleration of the car.
In the second situation, the car velocity goes from
u = 0
to
v = 15 m/s
So, we can use again the same equation to find t, the time it takes for the velocity of the car to change between these values: