2 years ago

How to calculate light year, minute and second?

1 answer:

5 0

Answer:

A light-year is the distance light travels in one year. How far is that? Multiply the number of seconds in one year by the number of miles or kilometers that light travels in one second, and there you have it: one light-year. It's about 5.88 trillion miles (9.5 trillion km).

Explanation:

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How large is the acceleration of a 25 kg mass with a net force of 75 N applied horizontally to it?

Sveta_85 [38]

Answer:

Explanation:

F = ma

a = F/m

a = 75/25

a = 3 m/s²

8 0

2 years ago

Which of the following would most likely be an example of a mass-transit disaster?

Aleonysh [2.5K]

Answer:

i think it is c if not im sorry if im wrong

Explanation:

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2 years ago

Which of the following is the best definition of vaporization

Vinvika [58]

Change of a liquid to a gas

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3 years ago

Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m

Alex Ar [27]

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

5 0

3 years ago

A Jeep accelerated at 2.2 m/s2 until after 18 seconds its displacement was 660 meters. Assuming the Jeep traveled in a straight

pogonyaev

Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660

Using the equation
$r = ut + \frac{1}{2} a {t}^{2}$
With 'u' being the initial velocity we want, we get:
$660 = 18u + 356.4$
So:
$18u = 303.6$
So:
$u = 16.8666$
So the original/initial velocity was 16.8666 or 16.87 m/s

Hope this helped

5 0

3 years ago