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3 years ago

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Ms. Clark earned $29,600 in her third year as a banker and $32,600 in her seventh year. How much did she make in her tenth year?

Assume that her yearly salaries form an arithmetic sequence. $28,100 $34,850 $55,550 $58,100

1 answer:

Scorpion4ik [409]3 years ago

7 0

Answer:

The answer is 28,100

Step-by-step explanation

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Of the 630 seats in the cafeteria 70% earners how many seats are being used

stepladder [879]

Answer:

441 seats are being used :]

Step-by-step explanation:

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3 years ago

A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu

Flura [38]

Answer:

The speed of car in miles per minute is $\frac{2}{3}$ miles per minute and

The speed of car in mile per hour is 40 miles per hour,

Step-by-step explanation:

Given as :

The distance cover by car = 2 $\frac{1}{3}$ = $\frac{7}{3}$ miles

The Time taken by car to cover distance = 3 $\frac{1}{2}$ min = $\frac{7}{2}$ min

The speed o car in miles per minute = S miles/min

So, Speed = $\dfrac{\textrm Distance}{\textrm Time}$

Or, S = $\frac{\frac{7}{3}}{\frac{7}{2}}$ mie per min

∴ S = $\frac{2}{3}$ miles per minute

Now, Let The speed of car in miles per hour = x miles/h

So, Time in hour = $\frac{7}{2}$ × $\frac{1}{60}$ = $\frac{7}{120}$ hours

So , Speed = $\dfrac{\textrm Distance}{\textrm Time}$

Or, x = $\frac{\frac{7}{3}}{\frac{7}{120}}$ miles per hours

Or, x = 40 miles per hours

Hence The speed of car in miles per minute is $\frac{2}{3}$ miles per minute and the speed of car in mile per hour is 40 miles per hour, answer

7 0

3 years ago

What's the domain (-2,6),(-5,-11),(3,7),(-5,0)

kodGreya [7K]

The domain is all the x values (range is y values). Remember to put the x values in numerical order.

So: Domain = {-5, -5, -2, 3}.

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3 years ago

Read 2 more answers

2х + Зу = 5<br> у= 5 - x <br> also need method

pav-90 [236]

Answer:

x=10, y=-5

Step-by-step explanation:

2x+3y=5, y= 5-x; change y to 5-x:

2x+3(5-x)=5

2x-3x+15=5

-x=5-15

-x=-10

x=10

=>y=5-x=5-10=-5

4 0

3 years ago

Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa

Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : $\mu = 15.45$

Standard deviation : $\sigma = 13.70$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 5 degrees

$z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76$

For x= 10 degrees

$z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40$

The P-value : $P(-0.76$

$=0.3445783-0.2236273=0.120951\approx0.1210$

In percent , $0.1210\times100=12.10\%$

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

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3 years ago