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Ivan
3 years ago
5

Write this number in standard notation. 1.986 x 10negative exponent 6 or 1.986 x 10^6

Chemistry
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

0.000001986

Explanation:

We have the number 1.986*10^{-6}. Standard notation would basically be this number without the 10^{-6} part.

To get rid of this part, we need to move the decimal point 6 places to the left (we go left because it's negative 6, indicating division).

So, when we move the decimal point 6 places to the left, the resulting number is: 0.000001986, with 5 zeros after the decimal point before a nonzero number.

Thus, the answer is 0.000001986.

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Provide the IUPAC names for
ollegr [7]

<u>Answer:</u>

<u>For a:</u> The IUPAC name of the compound is N-ethylethaneamide.

<u>For b:</u> The IUPAC name of the compound is N,N-diethylmethaneamide.

<u>For c:</u> The IUPAC name of the compound is ethyl pentanoate

<u>Explanation:</u>

To name a compound, first look for the longest possible carbon chain.

  • <u>For a:</u>

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is R-CO-NH_2, where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

  • <u>For b:</u>

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is R-CO-NH_2, where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

  • <u>For c:</u>

Esters are a kind of organic molecules having functional groups, R-COO-R' where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

6 0
3 years ago
What are the Physical changes for oxygen?
wolverine [178]

Answer:

Oxygen is a colorless, odorless, tasteless gas. It changes from a gas to a liquid at a temperature of -182.96°C (-297.33°F). The liquid formed has a slightly bluish color to it. Liquid oxygen can then be solidified or frozen at a temperature of -218.4°C (-361.2°F).

4 0
3 years ago
How to solve x² in differential​
g100num [7]

Answer:

x² = mutiphy by them self

Explanation:

4 0
3 years ago
10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride
Natali [406]

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

3 0
3 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
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