The reaction between Ag2CO3 and NaOH is shown by the equation below
Ag2CO3 + NaOH = Ag2O + Na2CO3 +H2O
we can determine the number of mole of sodium hydroxide
by (2.85 ml × 1) ÷ 1000 ml , since according to molarity 1 mole is contained in 100ml.
we get 0.00285 moles of NaOH
Using the mole ratio we can get the moles of Ag2CO3
Mole ratio: Ag2NO3 : NaOH = 1:1
Therefore, the moles of Ag2CO3 will be 0.00285 moles
but 1 mole of silver carbonate is equivalent to 275.8 g
Thus the mass will be calculated by 0.00285 moles × 275.8g = 0.78603g
Mass of silver carbonate required will be 0.78603g
Answer:
134.8 seconds is the half-life (in seconds) of the reaction for the initial 
concentration
Explanation:
Half life for second order kinetics is given by:
Integrated rate law for second order kinetics is given by:
= half life
k = rate constant
= initial concentration
a = Final concentration of reactant after time t
We have :
Initial concentration of ![C_2F_4=[a_o]=\frac{0.438 mol}{2.42 L}=0.1810 mol/L](https://tex.z-dn.net/?f=C_2F_4%3D%5Ba_o%5D%3D%5Cfrac%7B0.438%20mol%7D%7B2.42%20L%7D%3D0.1810%20mol%2FL)
Rate constant = k = 
134.8 seconds is the half-life (in seconds) of the reaction for the initial concentration
Answer:
Determining flammability can be as simple as holding a sample of the substance over a match. If it burns, it is flammable, leading to additional experiments to find more properties. Measuring the heat given off by the substance when it burns gives the heat of combustion.
Explanation:
