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2 years ago

Creatine phosphate functions in the muscle cell by ________.

Chemistry

1 answer:

Dmitriy789 [7]2 years ago

6 0

Answer:

Option B, storing energy that will transferred to ADP to resynthesize ATP

Explanation:

Creatine phosphate is a phosphorylated creatine molecule. It is present in muscle cells for storing energy. Creatine is an amono acid which is produced by the liver, kideny and pancreas.

Energy is stored in creatine phosphate for rapid release. Normal metabolism does not release energy as soon as released by creatine phosphate.

So, lots of creatine phosphate is present in energy rich muscle whereas very few present in fatigued muscle.

Creatine phosphate transfers its phosphate group to ADP quickly to regenerate ATP.

So, among the given option, option B is correct.

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Which of these bonds should be classified as ionic?

jolli1 [7]

Answer:

Na-O

Be-S

Explanation:

ionic bonds= metal and non metal

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2 years ago

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At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the

Aleks [24]

Answer:

$K_{p}=4.35\times 10^{-4}$

Explanation:

We know, $K_{p}=K_{c}(RT)^{\Delta n}$

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and $\Delta n$ is difference in sum of stoichiometric coefficient of products and reactants

Here $\Delta n=(2)-(2+1)=-1$ and T = 311 K

So, $K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}$

Hence value of equilibrium constant in terms of partial pressure $(K_{p})$ is $4.35\times 10^{-4}$

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2 years ago

What kind of group 1 atoms are the most reactive? a. Small atoms c. Atoms with the most electrons in the valence level b. Large

garri49 [273]

Answer:

large atoms

Explanation:

its kinda obvious

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2 years ago

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Which statement about the organisms whose fossils are found in the rock is correct?

o-na [289]

Answer:

Explanation:cause if organism w is a fossil and organism y is a rock the rock is way older than a fossil so a

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2 years ago

How many moles are in 8.63 x 103 atoms of Li?

Ira Lisetskai [31]

<h3>Answer:</h3>

1.43 × 10⁻²⁰ mol Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

8.63 × 10³ atoms Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 8.63 \cdot 10^3 \ atoms \ Li(\frac{1 \ mol \ Li}{6.022 \cdot 10^{23} \ atoms \ Li})$
Multiply/Divide: $\displaystyle 1.43355 \cdot 10^{-20} \ moles \ Li$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li

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2 years ago