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myrzilka [38]
3 years ago
11

A study is conducted to examine the effect of NaCl concentration on enzyme activity with the following results. Activity was tes

ted at various salt concentrations. Negative controls were conducted without enzyme. Which of the following is the best interpretation of the 0.27 p value when comparing the activity at 0.1 M to that 1t 0.05M
NaC1 Con (M) 0 0.01 0.02 0.05 0.1 0.2
Avg. Activity (nm/mg/min) 15.5 14 35.5 175.5 195 50.5
Standard Deviation 1.5 1.5 3.6 17 20 5
T-test vs 0.1M <0.05 <0.05 <0.05 0.27 NA <0.05
T-test vs Neg. Ctrl 0.56 0.6 <0.05 <0.05 <0.05 <0.05

a. The activity at 0.1 M NaCl is statistically significantly greater than that at 0.05M NaCl
b. There is a 27% difference between the average enzyme activities at 0.1 and 0.05 M NaCl
c. The variability among the replicates at 0.1 M and 0.05 M NaCl is 27%
d. The activity at 0.1 M NaCl is not statistically significantly greater than that at 0.05M NaCl
Chemistry
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

The answer is "Option D".

Explanation:

The behavior of 0.1M NaCl also isn't substantially larger objectively than those of 0.05M NaCl because a p-value above 0.05 (p>0.05) indicates no ability to tell differential and is a strong proof in favor of a null hypothesis.

The other wrong choices can be defined as follows:

  • Option A as it's just the reverse of the correct answer to the null.
  • Options B and C because p worth tests to support nor oppose the null hypothesis.
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3 years ago
A balloon full of air has a volume of 1.00L at a temperature of 23 °C. What is the balloon's volume at 33°C?
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V2= 1.03L

Explanation:

Start off with what you are given.

V^1: 1.00L

T^1: 23°C

V^2?

T^2: 33°C

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V^1/T^1 = V^2/T^2

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

(23+273 = 296)     (33+273 = 306)

Multiply crisscross

1.00/296= V^2/306

296V^2 = 306

Dividing both sides by 296 to isolate V2, we get

306/296 = 1.0337837837837837837837837837838

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