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myrzilka [38]
2 years ago
11

A study is conducted to examine the effect of NaCl concentration on enzyme activity with the following results. Activity was tes

ted at various salt concentrations. Negative controls were conducted without enzyme. Which of the following is the best interpretation of the 0.27 p value when comparing the activity at 0.1 M to that 1t 0.05M
NaC1 Con (M) 0 0.01 0.02 0.05 0.1 0.2
Avg. Activity (nm/mg/min) 15.5 14 35.5 175.5 195 50.5
Standard Deviation 1.5 1.5 3.6 17 20 5
T-test vs 0.1M <0.05 <0.05 <0.05 0.27 NA <0.05
T-test vs Neg. Ctrl 0.56 0.6 <0.05 <0.05 <0.05 <0.05

a. The activity at 0.1 M NaCl is statistically significantly greater than that at 0.05M NaCl
b. There is a 27% difference between the average enzyme activities at 0.1 and 0.05 M NaCl
c. The variability among the replicates at 0.1 M and 0.05 M NaCl is 27%
d. The activity at 0.1 M NaCl is not statistically significantly greater than that at 0.05M NaCl
Chemistry
1 answer:
Marina86 [1]2 years ago
3 0

Answer:

The answer is "Option D".

Explanation:

The behavior of 0.1M NaCl also isn't substantially larger objectively than those of 0.05M NaCl because a p-value above 0.05 (p>0.05) indicates no ability to tell differential and is a strong proof in favor of a null hypothesis.

The other wrong choices can be defined as follows:

  • Option A as it's just the reverse of the correct answer to the null.
  • Options B and C because p worth tests to support nor oppose the null hypothesis.
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The answer is 130.953 g of hydrogen gas.

Explanation:

Hydrogen gas is formed by two atoms of hydrogen (H), so its molecular formula is H₂. We can calculate is molecular weight as the product of the molar mass of H (1.008 g/mol):

Molecular weight H₂= molar mass of H x 2= 1.008 g/mol x 2= 2.01568 g

Finally, we obtain the number of mol of H₂ there is in the produced gas mass (264 g) by using the molecular weight as follows:

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The final mass rounded to 3 significant digits is 130.973 g

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