No if in the light it would be always half lit
First, light passes through the cornea. It bends the light inward. The light then passes through the pupil. After entering the eye through the pupil, the light passes through the lens. It focuses the light to create an image on the retina. It consists of light receptor cells called rods and cones. The rods and cones send nerve impulses about the image to the brain through the optic nerve. The visual cortex of the brain receives and interprets the information and tells you what you are seeing
Answer:
3.38m
Explanation:
Given parameters:
Time = 4s
Acceleration = 1.3m/s²
Unknown:
Magnitude of the displacement = ?
Solution:
The body starts at rest and the initial velocity is 0m/s. To solve this problem, we have to use the expression below;
S = Ut + 
at²
S = displacement
t is the time
a is the acceleration
U is the initial velocity
V is the final velocity
Insert the parameters and solve;
S = (0 x 4) + x 1.3² x 4 = 3.38m
We have Four (4). quantum number used in description of the energy state of an electron.
The Bohr model of atom addressed the problem of why electrons did not fall into the positive nucleus.
As per Rutherford's atomic model, electrons are revolving around the nucleus just like planets are revolving around the sun. But his description about electronic motion was against the Clark Maxwell's electromagnetic theory .
As per Maxwell any charged particle under accelerated motion will release energy. The electron is a negatively charged particle which under acceleration will come closer and closer to the nucleus and finally it will fall on the nucleus for which the whole atom will be destroyed. The path of electron will be a spiral one instead of circular. Hence Rutherford's theory could not explain the stability of nucleus.
Bohr addressed that electron in particular orbit has a fixed amount of energy .There will be no emission or absorption of energy as long as electron revolves around the nucleus.The electron will absorb energy when it will jump from ground state to excited state and will emit energy when it will jump from excited state to ground state.
Hence the option A is right,.
