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dusya [7]
3 years ago
10

Based on the atoms which ones would be in the same period?

Chemistry
2 answers:
statuscvo [17]3 years ago
4 0

Answer:

3&4 i belive if im wrong sorry im not very good at this i just know basic physics (im not sure if thats physics tho)

Explanation:

Neko [114]3 years ago
3 0

Vas happenin!


Atom 1= 6 valence electrons

Atom 2= 3 valence electrons

Atom 3= 8 valence electrons

Atom 4= 6 valence electrons



I would say atom 3


Hope this helps

-Zayn Malik
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3 years ago
Name two compounds in unpolluted air?
goblinko [34]
Nitrogen and oxygen are in unpolluted air

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3 years ago
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sergiy2304 [10]
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The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

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3 0
3 years ago
A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/
galben [10]
To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
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7 0
3 years ago
Read 2 more answers
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