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jeka57 [31]
3 years ago
6

Why is it more difficult to breathe at high altitudes rather than low

Chemistry
2 answers:
Dmitrij [34]3 years ago
6 0
As you travel higher, the air begins to thin out which makes it harder for you to breathe. There is less oxygen as you travel higher.
Katena32 [7]3 years ago
5 0
Because the air gets thinner. The air at higher altitudes is more uncontaminated oxygen, cleaner air, whereas at low altitudes, air is more contaminated by smog and pollution from factories, power plants, etc.
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Calculate the number of atoms of H in 22.5g of H2O
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2.5gm answer ....2/18x22.5
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How does biodiversity generate the economy?
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Biodiversity helps an economy grow and develop over time because such as the circle of life we need other things in order to evolve such as trees so we can be able to breathe and plants so the herbivores can eat so we can eat them because we are all part of a cycle and in order to keep the cycle going we need biodiversity to keep the food chain going and our economy well and lifted
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3 years ago
Define relative atomic mass?​
SVEN [57.7K]

Answer:

The relative atomic mass of an element is defined as the weight in grams of the number of atoms of the element contained in 12.00 g of carbon-12.

Or

Its just another term for atomic mass.

Explanation:

6 0
2 years ago
Explain how temperature and amount of precipitation can affect the type of plants and animals found in the grassland biome?
MArishka [77]
Temperature grasslands have hot summers and cold winters. Summer temperatures can be well over 100 degrees Fahrenheit, while winter temperatures can be as low as -40 degrees Fahrenheit. They typically have between 10 and 35 inches of precipitation a year, much of it occurring in the late spring and early summer. As climate conditions shift geographically so will the distributions of many plants and animals. The relatively flat terrain of grasslands increases vulnerability to climate change impacts, because habitats and species must migrate long distances to compensate for temperature shift.
3 0
3 years ago
A chemist titrates 220.0 mL of a 0.1917M propionic acid (HC2H5CO2) solution with 0.1787 M KOH solution at 25°C. Calculate the p
natima [27]

Answer : The pH at equivalence is, 9.08

Explanation : Given,

Concentration of HC_2H_5CO_2 = 0.1917 M

Volume of HC_2H_5CO_2 = 220.0 mL = 0.220 L (1 L = 1000 mL)

First we have to calculate the moles of HC_2H_5CO_2

\text{Moles of }HC_2H_5CO_2=\text{Concentration of }HC_2H_5CO_2\times \text{Volume of }HC_2H_5CO_2

\text{Moles of }HC_2H_5CO_2=0.1917M\times 0.220L=0.0422

As we known that at equivalent point, the moles of HC_2H_5CO_2 and KOH are equal.

So, Moles of KOH = Moles of HC_2H_5CO_2 = 0.0422 mol

Now we have to calculate the volume of KOH.

\text{Volume of }KOH=\frac{\text{Moles of }KOH}{\text{Concentration of }KOH}

\text{Volume of }KOH=\frac{0.0422mol}{0.1787M}

\text{Volume of }KOH=0.00754

Total volume of solution = 0.220 L + 0.00754 L = 0.22754 L

Now we have to calculate the concentration of KCN.

The balanced equilibrium reaction will be:

HC_2H_5CO_2+KOH\rightleftharpoons C_2H_5CO_2K+H_2O

Moles of C_2H_5CO_2K = 0.0422 mol

\text{Concentration of }C_2H_5CO_2K=\frac{0.0422mol}{0.22754L}=0.1855M

At equivalent point,

pH=\frac{1}{2}[pK_w+pK_a+\log C]

Given:

pK_w=14\\\\pK_a=4.89\\\\C=0.1855M

Now put all the given values in the above expression, we get:

pH=\frac{1}{2}[14+4.89+\log (0.1855)]

pH=9.08

Therefore, the pH at equivalence is, 9.08

6 0
3 years ago
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