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Montano1993 [528]
3 years ago
5

How many fe(ii) ions are there in 25.0 g of feso4?

Chemistry
2 answers:
lesya692 [45]3 years ago
4 0

Hey there!:

1 mole of FeSO4 = 151.8 g/mol

25.0 g change to mole  = 25.0 / 151.8

moles of FeSO4 = 0.165 moles

One mole of any substance has  6.02*10²³ units

0.165 moles to get the number of Fe ( II ) ions :

number of  Fe(II) ion = 0.165 * ( 6.02*10²³ )

number of Fe ( II ) ion = 9.93*10²² units


Sati [7]3 years ago
3 0

Answer:

ions_{Fe^{2+}}=9.90x10^{22}ionsFe^{2+}

Explanation:

Hello,

In this case, the following mole-mass relationship, is applied to obtain the ions of iron (II) in 25.0 g of iron (II) sulfate whose molar mass is 152 g/mol:

ions_{Fe^{2+}}=25.0gFeSO_4*\frac{1molFeSO_4}{152gFeSO_4}*\frac{1molFe^{2+}}{1molFeSO_4}*\frac{6.022x10^{23}ionsFe^{2+}}{1molFe^{2+}} \\ions_{Fe^{2+}}=9.90x10^{22}ionsFe^{2+}

Best regards.

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A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole
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Answer: The molecular formula will be C_6O_3H_{12}

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Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

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5 0
3 years ago
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Answer:

340 grams Ca₃P₂ (2 sig. figs.)

Explanation:

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5.6 mole + excess =>   ? grams

Convert the 'known' to a coefficient of 1 by dividing all coefficients by 3.

=>  Ca   +   2/3P   =>    1/3Ca₃P₂

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