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Aleks04 [339]
3 years ago
8

What is the ph of a 0.20 M solution of NH4Cl? [Kb(NH3) = 1.8 x 10^-5]

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
8 0

"NH4+ <----> NH3 + H+  

The constant of this equilibrium is: K = Kw / Kb = 1 x 10^-14 / 1.8 x 10^-5 =5.56 x 10^-10  

5.56 x 10^-10 = x^2 / 0.20-x  

x = [H+] =1.1 x 10^-5 M  

pH = 5.0"

ad-work [718]3 years ago
5 0

Answer:

5.0

Explanation:

NH₄Cl is a strong electrolyte that ionizes according to the following equation.

NH₄Cl(aq) → NH₄⁺(aq) + Cl⁻(aq)

NH₄⁺ is a weak acid according to the following equation.

NH₄⁺(aq) ⇄ NH₃(aq) + H⁺(aq)

Given Kb for NH₃, we can calculate the Ka for NH₄⁺.

Ka. Kb = Kw

Ka = Kw / Kb = 10⁻¹⁴/1.8 × 10⁻⁵ = 5.6 × 10⁻¹⁰

For a weak acid, we can find [H⁺] using the following expression.

[H⁺] = √(Ca × Ka) = √(0.20 × 5.6 × 10⁻¹⁰) = 1.1 × 10⁻⁵ M

where,

Ca: concentration of the acid

The pH is

pH = -log [H⁺] = -log 1.1 × 10⁻⁵ = 5.0

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2 CuCl2 + 4 KI → 2 CuI + 4 KCl + I2
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Explanation:

This is a simple stoichiometry proboe. that I would set up like this:

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Hope this helps :)

7 0
3 years ago
Which 2 elements when combined NOT alloys?
Volgvan

Answer:

Oxygen and sulfur

Explanation:

Alloys consist of metals fused together sometimes with additional components, such as carbon, to prevent metals from corrosion.

Oxygen and sulfur are two compounds consisting of non-metal atoms, O and S. Combining oxygen with sulfur would actually produce sulfur dioxide, a gas, in contrast to a metallic substance that is fused with some other metal or carbon.

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6 0
3 years ago
0.0009547863= x^-1.644
Andrej [43]

Answer: 68.71317831

Explanation:

5 0
3 years ago
How many moles of SnF2 will be produced along with 48 grams of H2
wolverine [178]

Answer:

24 moles

Explanation:

given data

H_2 = 48 grams

to find out

how many moles of SnF_2 will be produced

solution

we know that Stoichiometry is here as

Sn+2HF\rightarrow SnF_2+H_2      ......................1

so we get here mole of solute H_2 that is express as

mole = \frac{\text{given mass}}{\text{Molar Mass}}      ..........................2

put here value for H_2  

mole = \frac{48}{2}  

mole of H_2 = 24 mole

and

we can say that here as per equation 1 that one mole of H_2  is go with one mole of SnF_2

so here H_2 24 mole is go with 24 moles mole of SnF_2  

so we can say SnF_2 will be produced 24 moles

5 0
3 years ago
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