NaH(s)+ H2O (l)=>NaOH(aq)+H2(g)
You want to calculate the mass of NaH, I assume. Otherwise, the question isn't clear. It simply says calculate the mass(??)
So, calculate the moles of H2 gas that satisfy the conditions of 982 ml at 28ºC and 765 torr. But you must subtract the vapor pressure of water at 28º to get the actual pressure of the H2 gas. So, the actual conditions are 982 ml (0.982 L) and 301 K and 765-28 = 737 torr.
PV = nRT
n = PV/RT = (737 torr)(0.982 L)/(62.4 L-torr/Kmol)(301 K)
n = 0.0385 moles H2
moles NaH needed = 0.0385 moles H2 x 1 mole NaH/mole H2 = 0.0385 moles NaH required
mass of NaH needed = 0.0385 moles x 24 g/mole = 0.925 g NaH
Brainliest Please :)
The limiting reactant can be determined by calculating the
moles supplied / moles stoich ratio and the lowest is the limiting reactant.
Fe(CO)5 ratio = [6 g / 195.9 g/mol] / 1
Fe(CO)5 ratio = 0.0306
PF3 ratio = [4 g / 87.97 g/mol] / 2
PF3 ratio = 0.0227
H2 ratio = [4 g / 2 g/mol] / 1
H2 ratio = 2
<span>We can see that PF3 has the lowest ratio, so it is the
limiting reactant.</span>
Answer: An organism's niche includes food, shelter, its predators, the temperature, the amount of moisture the organism needs to survive, etc. When two or more individuals or populations try to use the same limited resources such as food, water, shelter, space, or sunlight, it is called competition.
Explanation: Hope that helps?
