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nasty-shy [4]
3 years ago
14

What are the assumptions we make when using the gas collection apparatus in this lab? (Select all that apply)

Chemistry
1 answer:
stich3 [128]3 years ago
7 0

We collect gas using special apparatus because most gasses cannot be seen, hence we may find it difficult to tell if our test tube is filled, and the best method to collect gas is through water.

One of the apparatus we use in collecting gas is pneumatic trough. A pneumatic trough is a piece of laboratory apparatus used for collecting gases, such as hydrogen, oxygen and nitrogen.

<em>Assumptions we make when using the gas collection apparatus</em>

The assumption we make is on the basis of the ideal gas assumption which are:

  • The gas consists of a large number of molecules, which are in random motion and obey Newton's laws of motion;
  • The volume of the molecules is negligibly small compared to the volume occupied by the gas; and
  • No forces act on the molecules except during elastic collisions of negligible duration.

For more information on the ideal gas assumption kindly visit

brainly.com/question/16829906

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Answer:

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How can noble gas electron configuration be achieved?
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A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium we make the substitution of (Ne) for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes (Ne) 3s1.

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2 years ago
The Aufbau Principle describes that
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Answer:

electrons fill lower energy levels first before occupying higher energy levels.

Explanation:

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4 0
3 years ago
For water at 30C and 1 atm: a= 3.04x10^-4 k^-1 , k =4.52x10^-5 atm ^-1 = 4.46 x10^-10 m^2/N, cpm= 75.3j/9molk), Vm =18.1cm^3/mol
Lapatulllka [165]

Answer:

C_{vm} of water at 30C and 1 atm is 256.834 J/mol·K.

Explanation:

To solve the question, we note the Maxwell relation such as

C_{pm}-C_{vm}=\frac{9T\alpha ^2 V }{K}

Where:

C_{pm} = Specific heat of gas at constant pressure = 75.3 J/mol·K

C_{vm} = Specific heat of gas at constant volume = Required

T = Temperature = 30 °C = 303.15 K

α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹

K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹

Therefore,

75.3 - C_v = \frac{9\times 303.15 \times (3.04 \times 10^{-1} 1.81  \times 10^{-5}  }{4.52 \times 10^{-5} }

C_{vm}  = \frac{9\times 303.15 \times (3.04 \times 10^{-1} 1.81  \times 10^{-5}  }{4.52 \times 10^{-5} } - 75.3 = 256.834 J/mol·K.

8 0
3 years ago
What is the interval used on the y-axis of this graph?
bezimeni [28]

Answer:

5

Explanation:

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7 0
3 years ago
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