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Firlakuza [10]
3 years ago
13

100 PNTS ANSWER ASAP PLZ The density of a particular small rubber ball is 1.1 g/cm3. It was dropped into a 100 mL beaker filled

with 50 mL each of ethanol and distilled water. Which is the most accurate description of what happened to the rubber ball in the beaker? A. It sank below the ethanol and distilled water. B. It floated on top of the ethanol and distilled water. C. It floated on top of the ethanol, but sank below the distilled water. D. It sank below the ethanol, but floated on top of the distilled water.
Chemistry
2 answers:
Klio2033 [76]3 years ago
6 0

Answer:

A. It sank below the ethanol and distilled water.

Explanation:

I just tok the quiz! :)

AlekseyPX3 years ago
3 0

Answer:

a

Explanation:

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Convert 3.52 × 10^22 atoms of gold to moles​
IrinaVladis [17]

Answer:

5.85 x 10⁻² mol Au

Explanation:

Divide the atoms of gold with Avogadro's number to find the solution.

5 0
3 years ago
The The thermal conductivity of a sheet of rigid, extruded insulation is reported to be k=0.029 W/ m measured temperature differ
vfiekz [6]

Answer:

Heat flux = 13.92 W/m2

Rate of heat transfer throug the 3m x 3m sheet = 125.28 W

The thermal resistance of the 3x3m sheet is 0.0958 K/W

Explanation:

The rate of heat transfer through a 3m x 3m sheet of insulation can be calculated as:

q=-k*A*\frac{\Delta T}{\Delta X}\\\\q=-0.029\frac{W}{m*K}*(3m*3m)*\frac{12K}{0.025m}  =125.28W

The heat flux can be defined as the amount of heat flow by unit of area.

Using the previous calculation, we can estimate the heat flux:

heat \, flux=\frac{q}{A}=\frac{125.28 W}{9 m^{2} }  =13.92 W/m^{2}

It can also be calculated as:

q/A=-k*\frac{\Delta T}{\Delta X}

The thermal resistance can be expressed as

\Delta T=R_t*Q\\R_t=\Delta T/Q=\frac{\Delta X}{k*A}

For the 3m x 3m sheet, the thermal resistance is

R_t = \frac{\Delta X}{k*A}=\frac{0.025m}{0.029W/mK*9m^{2}}=0.0958 \, K/W

4 0
3 years ago
This decomposition is first order with respect to phosphine, and has a half‑life of 35.0 s at 953 K. Calculate the partial press
Solnce55 [7]

Answer:

0.57 atm

Explanation:

When a a reaction is first order, we have from calculus the following relation:

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this case ) after a time, t

           [A]₀ is the initial concentration of A

           k is the rate constant, and

           t is the time

We also know that for a first order reaction

           k = 0.693/ t 1/2

wnere t 1/2 is the half-life.

This equation is derived for the case when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, lets first find k from the half life time, and then solve for t = 70.5 s

k = 0.693 /  35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from the ideal gas law we know pV = nRT, so the volumes cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀  = - kt

thus:

(pPH₃ )t  = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

3 0
3 years ago
Help plz i need it my mom is mad at me for not knowing this
ohaa [14]
Lol ok ill help the answer is true and she SHOULDNT be mad at you
5 0
3 years ago
The bond between which two atoms is most
MariettaO [177]
The answer would be option 4
8 0
2 years ago
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