Answer:
455 Kcal
Explanation:
2Cl2(g) + 7O2(g) + 130kcal → 2Cl2O7(g)
Rearranging we get,
2Cl2(g) + 7O2(g) → 2Cl2O7(g) Δ H = 130 kcal . mol⁻¹
So for per mol reaction will be as above.
In case of 7 mols of product, we need 7/2 mole ratio x 130 = 455 Kcal
Answer:
The answer is 5.7 minutes
Explanation:
A first-order reaction follow the law of
. Where <em>[A]</em> is the concentration of the reactant at any <em>t</em> time of the reaction,
is the concentration of the reactant at the beginning of the reaction and <em>k</em> is the rate constant.
Dropping the concentration of the reactant to 6.25% means the concentration of A at the end of the reaction has to be
. And the rate constant (<em>k</em>) is 8.10×10−3 s−1
Replacing the equation of the law:
![Ln \frac{6.25}{100}.[A]_{0} = -8.10x10^{-3}s^{-1}.t + Ln[A]_{0}](https://tex.z-dn.net/?f=Ln%20%5Cfrac%7B6.25%7D%7B100%7D.%5BA%5D_%7B0%7D%20%3D%20-8.10x10%5E%7B-3%7Ds%5E%7B-1%7D.t%20%2B%20Ln%5BA%5D_%7B0%7D)
Clearing the equation:
![Ln [A]_{0}.\frac{6.25}{100} - Ln [A]_{0} = -8.10x10^{-3}s^{-1}.t](https://tex.z-dn.net/?f=Ln%20%5BA%5D_%7B0%7D.%5Cfrac%7B6.25%7D%7B100%7D%20-%20Ln%20%5BA%5D_%7B0%7D%20%3D%20-8.10x10%5E%7B-3%7Ds%5E%7B-1%7D.t)
<em>Considering the property of logarithms: </em>
Using the property:
![Ln \frac{[A]_{0}}{[A]_{0}}.\frac{6.25}{100} = -8.10x10^{-3}s^{-1}.t](https://tex.z-dn.net/?f=Ln%20%5Cfrac%7B%5BA%5D_%7B0%7D%7D%7B%5BA%5D_%7B0%7D%7D.%5Cfrac%7B6.25%7D%7B100%7D%20%3D%20-8.10x10%5E%7B-3%7Ds%5E%7B-1%7D.t)
Clearing <em>t </em>and solving:

The answer is in the unit of seconds, but every minute contains 60 seconds, converting the units:

There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.

To find:
Bonds on the reactant side
Solution:

Reactants in the reaction = 
The bond between nitrogen atoms in single
molecule = N≡N (triple bond)
Then in two
molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single
molecule = H-H (single bond)
Then in three
molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single
molecule = 3 N-H (single bond)
Then in two
molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
Learn more about reactants and products here:
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brainly.com/question/20602904?referrer=searchResults
Elements and compounds are both examples of pure substances. Compounds are substances that are made up of more than one type of atom. Elements are the simplest substances made up of only one type of atom. i hope that helps:)
109/8.56=12.7
50+12.7
V=62.7
Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer