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3 years ago

how is the motion of the particles in the soup different after the temperature of the soup increases?

Physics

1 answer:

eduard3 years ago

6 0

The particles break down and liquify as the tempeture increases.

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How is refraction different from reflection?

olga_2 [115]

<span>The angle of refraction is not necessarily equal to the angle
of incidence, whereas the angle of reflection always is.</span>

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3 years ago

A sinusoidal wave traveling on a string has a period of 0.20 s, a wavelength of 32 cm, and an amplitude of 3 cm. The speed of th

Finger [1]

Answer:

$v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}$

Explanation:

If we have a periodic wave we need to satisfy the following basic relationship:

$v = \lambda f$

From the last formula we see that the velocity is proportional fo the frequency.

For this case we have the following info given by the problem:

$T= 0.2 s, \lambda =32 cm* \frac{1m}{100cm} =0.32 m, A= 3cm*\frac{1m}{100 cm}=0.03 m$

We know that the frequency is the reciprocal of the period so we have this formula:

$f = \frac{1}{T}$

And if we replace we got:

$f =\frac{1}{0.2 s}= 5Hz$

Now since we have the value for the wavelength we can find the velocity like this:

$v = 0.32 m * 5Hz = 1.6 \frac{m}{s}$

And if we convert this into cm/s we got:

$v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}$

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3 years ago

Neo and the agent stand in different locations and the length of the line between them (their distance apart) is a measurement o

scZoUnD [109]

I think their distance is a measurement of : B. space in two dimension

In two-dimensional space, both directions located in the same plane , and the distance in locations only separated by width and length (there is no volume in this model)

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3 years ago

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A 0.15-m straight wire moves with a constant velocity of 7.0 m/s perpendicularly

lana66690 [7]

Answer: force is 0.42 N

Explanation: F = l·v·B

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2 years ago

A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.50 T. The field is then adjusted so that a

bixtya [17]

Answer:

$B_e = 2.72 \times 10^{-4} T$

Explanation:

As we know that when charge particle is projected in perpendicular magnetic field then the radius of the charge particle is given as

$F = qvB$

$\frac{mv^2}{r} = qvB$

now we have

$r = \frac{mv}{qB}$

since here radius of proton and electron will be same

so we will have

$r_e = r_p$

$\frac{m_e v}{q_e B_e} = \frac{m_p v}{q_p B_p}$

so we have

$B_e = \frac{B_p m_e}{m_p}$

given that

$B_p = 0.50 T$

$m_e = 9.11 \times 10^{-31} kg$

$m_p = 1.67 \times 10^{-27} kg$

so we have

$B_e = \frac{0.50(9.11\times 10^{-31})}{1.67\times 10^{-27}}$

$B_e = 2.72 \times 10^{-4} T$

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3 years ago

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