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svp [43]
3 years ago
12

A ball thrown horizontall at 22.2 m/s from the roof of a building lands 36.0m from the base of the building. How tall is the bui

lding?
Physics
1 answer:
vekshin13 years ago
8 0
Velocity of the ball (v) = 22.2 m/s
Distance from the base of the building where the ball falls (d) = 36.0m
We know that, Velocity (v) = distance (d) / time (t)
From the above equation,
Time (t) = distance (d) / velocity (v)
Substituting the values for distance and velocity in the above equation,
Time = 36.0/22.2 = 1.62 seconds

When the ball is falling down, it accelerates due to gravity
This acceleration (a) = 9.8 m/s²

Now we need to find the height of the building.
The equation of motion for an object with constant acceleration is,
s = ut + 1/2 at²
Where,
s = vertical displacement, which is height of the building in our case
u = initial velocity of the ball = 0

Substituting all the above values in the equation of motion,
s = (0 × 1.62) + (1/2 × 9.8 × 1.62²)
s = 0 + (25.72/2) = 12.86 m = 12.9 m which is the height of the building

Therefore the building is 12.9m tall

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Since it is restricted at both ends, λ/2 = length of string

λ/2 = 1.5m
λ = 1.5*2 = 3m
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4 0
3 years ago
What is the voltage across a semiconductor bar if the current through it is 0.17 A? The electron concentration in the bar is 2.7
Anastaziya [24]

Answer:

The voltage across a semiconductor bar is 0.068 V.

Explanation:

Given that,

Current = 0.17 A

Electron concentration n= 2.7\times10^{18}\ cm^{-3}

Electron mobility \mu=1000 cm^2/Vs

Length = 0.1 mm

Area = 500 μm²

We need to calculate the resistivity

Using formula of resistivity

\sigma=n\times q\times \mu

\rho=\dfrac{1}{\sigma}

Put the value into the formula

\rho=\dfrac{1}{2.7\times10^{18}\times10^{6}\times1.6\times10^{-19}\times1000\times10^{-4}}

\rho=2\ \mu \Omega m

We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

R=\dfrac{2\times10^{-6}\times0.1\times10^{-3}}{500\times(10^{-6})^2}

R=0.4\ \Omega

We need to calculate the voltage

Using formula of voltage

V= IR

Put the value into the formula

V=0.17\times0.4

V=0.068\ V

Hence, The voltage across a semiconductor bar is 0.068 V.

6 0
3 years ago
I need an expert in physics for help
Elodia [21]
Whatcha need help with ????????
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2 years ago
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