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Hunter-Best [27]
3 years ago
8

Plz help me with #4 it’s 15 points!!

Physics
1 answer:
vovangra [49]3 years ago
3 0
When you push a coin across a Table , the unbalanced force is that force which cause the change in motion of the object.That's why the coin is moving forward.So force applied by my fingers and Frictional force applied by the table on the coin are Unbalanced forces.
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What is the function of layer of air trapped under the hovercraft​
aev [14]

Answer:b

Explanation:

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How do you determine the acceleration of an object?
Mekhanik [1.2K]

according to the second law of dynamics F = m • a => a = F / m

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A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the w
Leto [7]

A) 140 degrees

First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is

T = 32 s

So the angular velocity is

\omega=\frac{2\pi}{T}=\frac{2\pi}{32 s}=0.20 rad/s

Assuming the wheel is moving at constant angular velocity, we can now calculate the angular displacement with respect to the initial position:

\theta= \omega t

and substituting t = 75 seconds, we find

\theta= (0.20 rad/s)(75 s)=15 rad

In degrees, it is

15 rad: x = 2\pi rad : 360^{\circ}\\
x=\frac{(15 rad)(360^{\circ})}{2\pi}=860^{\circ} = 140^{\circ}

So, the new position is 140 degrees from the initial position at the top.

B) 2.7 m/s

The tangential speed, v, of a point at the egde of the wheel is given by

v=\omega r

where we have

\omega=0.20 rad/s

r = d/2 = (27 m)/2=13.5 m is the radius of the wheel

Substituting into the equation, we find

v=(0.20 rad/s)(13.5 m)=2.7 m/s

6 0
3 years ago
Suppose a certain car supplies a constant deceleration of A meter per second per second. If it is traveling at 90km/hr. When. th
aksik [14]

Answer:

i)-6.25m/s

ii)18 metres

iii)26.5 m/s or 95.4 km/hr

Explanation:

Firstly convert 90km/hr to m/s

90 × 1000/3600 = 25m/s

(i) Apply v^2 = u^2 + 2As...where v(0m/s) is the final speed and u(25m/s) is initial speed and also s is the distance moved through(50 metres)

0 = (25)^2 + 2A(50)

0 = 625 + 100A....then moved the other value to one

-625 = 100A

Hence A = -6.25m/s^2(where the negative just tells us that its deceleration)

(ii) Firstly convert 54km/hr to m/s

In which this is 54 × 1000/3600 = 15m/s

then apply the same formula as that in (i)

0 = (15)^2 + 2(-6.25)s

-225 = -12.5s

Hence the stopping distance = 18metres

(iii) Apply the same formula and always remember that the deceleration values is the same throughout this question

0 = u^2 + 2(-6.25)(56)

u^2 = 700

Hence the speed that the car was travelling at is the,square root of 700 = 26.5m/s

In km/hr....26.5 × 3600/1000 = 95.4 km/hr

3 0
2 years ago
describe what a person in the passenger seat will fill out the car ages poin describe what a person in the passenger seat will f
dedylja [7]

There are several possibilities.  Here are a few that occur to me:

--  If Point-A is the summit of Pike's Peak, he may feel somewhat
short of breath.

-- If Point-A is his grandmother's house, he may feel a great sense
of pleasant anticipation.

-- If Point-A is his office on Monday morning, then he may feel
a tightening sensation in his chest.;

-- If Point-A is his home on Friday afternoon, then he feels the
effects of a slow and steady drop in his blood pressure.

I finer point might be put to it if we had any idea of where
Point-A is, and what it represents in the grand scheme
of things.

5 0
2 years ago
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