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Arte-miy333 [17]
3 years ago
8

The SI unit of power is the

Physics
2 answers:
Oksanka [162]3 years ago
4 0
Watt (W).............
fgiga [73]3 years ago
3 0
<span>Power is measured in watts. A watt is the power that it takes to do one joule ofwork in one second. It can be found using the formula <span>P=<span>Wt</span></span>. (In this formula, W stands for "work.")</span><span><span>Large amounts of energy can be measured in kilowatts (<span>1kW=1×<span>103</span>W</span>), megawatts (<span>1MW=1×<span>106</span>W</span>), or gigawatts (<span>1GW=1×<span>109</span>W</span>).</span><span><span> This is helpful</span><span> This is confusing</span></span></span><span>The watt is named James Watt, who invented an older unit of power: the horsepower.</span>
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Cecily is inflating one of her bicycle tyres with the pump below. When she pushes the plunger down, does the volume of the gas i
Alexxandr [17]

Answer:

See the explanation below

Explanation:

This problem can be better understood graphically, so in the attached image we will use a diagram of a positive displacement air pump.

We can see that when she pushes the plunger, we see that the volume decreases.

8 0
3 years ago
A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s
Irina-Kira [14]

Answer:

v = 14.78m/s

Explanation:

Given

KE = 150J

p = 20.3kgm/s

Required

Determine the object's speed

Kinetic Energy is calculated as:

KE = \frac{1}{2}mv^2

Make m the subject

m = \frac{2KE}{v^2}

Momentum is calculated as:

p = mv

Make m the subject

m = \frac{p}{v}

So, we have:

m = \frac{p}{v} and m = \frac{2KE}{v^2}

Equate both expressions: m = m

\frac{2KE}{v^2} = \frac{p}{v}

Multiply both sides by v

v *  \frac{2KE}{v^2} = \frac{p}{v}*v

\frac{2KE}{v} = p

Make v the subject

v = \frac{2KE}{p}

Substitute KE = 150J and p = 20.3kgm/s

v = \frac{2 * 150}{20.3}

v = \frac{300}{20.3}

v = 14.78m/s

5 0
3 years ago
An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?
Romashka [77]
The correct answer is: Average Power  = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2<span> / R </span>= (100 * 100) / (2 * 10) = <span>500 W</span>
3 0
4 years ago
If you place a magnet under a clear dish, and sprinkle iron fillings over it, above what part of the magnet will most of the fil
xxTIMURxx [149]

round the corners of the magnet that where it is stronger

hope this helps :)

5 0
3 years ago
Read 2 more answers
1. How much energy is needed just to melt 0.56kg of ice at 0◦ C?
ivann1987 [24]

Answer:

This will require 266.9 of heat energy.

Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:The mass of the material, m The temperature change that occurs,  ΔT The specific heat capacity of the material,

c

(which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.

Here is a source of values of

c for different substances:

Once you have all that, this is the equation:

Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of c is 4.186g°C So, Q=750×4.186×85=266=858=266.858

5 0
3 years ago
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