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lawyer [7]
2 years ago
11

Two rods are identical, except that one is brass (Y = 9.0 × 1010 N/m2) and one is tungsten (Y = 3.6 × 1011 N/m2). A force causes

the brass rod to stretch by 3.0 × 10-6 m. What is the amount of stretch ΔLTungsten for the tungsten rod when the same force is applied to it?
Physics
1 answer:
PIT_PIT [208]2 years ago
8 0

To solve this problem it is necessary to apply the concepts related to Young's Module, and find the radius that gives the ratio between the two given materials. Young's module can be defined as,

Y=\frac{FL}{A \Delta L}

Where,

F= Force

L = Initial Length

A = Cross-sectional Area

\Delta L = Change in Length

Re-arrange the equation to find the change in Length we have,

\Delta L = \frac{FL}{AY}

If both the Force, as the Area and the initial length are considered constant, we can realize directly that the change in length is inversely proportional to Young's Module, therefore

\Delta L \propto \frac{1}{Y}

Applying this concept to that of the two materials (Brass and Tungsten),

\frac{\Delta L_T}{\Delta L_B} = \frac{Y_B}{Y_T}

\frac{\Delta L_T}{\Delta L_B} = \frac{9*10^{10}}{3.6*10^{11}}

\frac{\Delta L_T}{\Delta L_B} = 0.25

If the force caused 3 * 10^ {- 6}m to be stretched, the tungsten will stretch 0.25 of that ratio

L_T = 3*10^{-6}*0.25

L_T = 7.5*10^{-7}m

Therefore the amount of stretch of Tungsten is 7.5*10^{-7}m

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2 years ago
E14. A ball rolls off a table with a horizontal velocity of 5 m/s. If
Shkiper50 [21]

a) Vertical velocity: 5.9 m/s

b) Horizontal velocity: 5 m/s

Explanation:

a)

The motion of the ball is the motion of a projectile, which consists of two independent motions:

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- A uniformly accelerated motion (constant acceleration) along the vertical direction

Here we want to find the vertical component of the ball's velocity. This can be done by using the suvat equation for the vertical motion:

v_y = u_y +gt

where:

v_y is the vertical velocity at time t

u_y=0 is the initial vertical velocity (zero because the ball has been thrown horizontally)

g=10 m/s^2 is the acceleration of gravity (here we take downward as positive direction)

Substituting t = 0.6 s, which is the total time of flight, we find the vertical velocity of the ball just before it hits the ground:

v_y=0+(9.8)(0.6)=5.9 m/s

b)

The motion along the vertical direction is an accelerated motion, because there is a force (the force of gravity) acting on the ball and that it causes an acceleration in the ball.

However, there are no forces acting in the horizontal direction on the ball (if we neglect the air resistance): this means that the acceleration of the ball in the horizontal direction is zero.

As a consequence, this also means that the horizontal component of the ball's velocity is constant during the motion.

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3 years ago
A proton is 0.9 meters away from a 1.4 C charge. What is the magnitude of the electric force between the proton and the charge
Digiron [165]

Answer:

F = 2.49 x 10⁻⁹ N

Explanation:

The electrostatic force between two charged bodies is given by Colomb's Law:

F = \frac{kq_1q_2}{r^2}\\

where,

F = Electrostatic Force = ?

k = colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = charge on proton = 1.6 x 10⁻¹⁹ C

q₂ = second charge = 1.4 C

r = distace between charges = 0.9 m

Therefore,

F = \frac{(9\ x\ 10^9\ N.m^2/C^2)(1.6\ x\ 10^{-19}\ C)(1.4\ C)}{(0.9\ m)^2}

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8 0
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11111nata11111 [884]

Answer:

M_c = 100.8 Nm

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- We see that the vertical component of force at point A passes through C.

Hence, its moment about C is zero.

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