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lawyer [7]
2 years ago
11

Two rods are identical, except that one is brass (Y = 9.0 × 1010 N/m2) and one is tungsten (Y = 3.6 × 1011 N/m2). A force causes

the brass rod to stretch by 3.0 × 10-6 m. What is the amount of stretch ΔLTungsten for the tungsten rod when the same force is applied to it?
Physics
1 answer:
PIT_PIT [208]2 years ago
8 0

To solve this problem it is necessary to apply the concepts related to Young's Module, and find the radius that gives the ratio between the two given materials. Young's module can be defined as,

Y=\frac{FL}{A \Delta L}

Where,

F= Force

L = Initial Length

A = Cross-sectional Area

\Delta L = Change in Length

Re-arrange the equation to find the change in Length we have,

\Delta L = \frac{FL}{AY}

If both the Force, as the Area and the initial length are considered constant, we can realize directly that the change in length is inversely proportional to Young's Module, therefore

\Delta L \propto \frac{1}{Y}

Applying this concept to that of the two materials (Brass and Tungsten),

\frac{\Delta L_T}{\Delta L_B} = \frac{Y_B}{Y_T}

\frac{\Delta L_T}{\Delta L_B} = \frac{9*10^{10}}{3.6*10^{11}}

\frac{\Delta L_T}{\Delta L_B} = 0.25

If the force caused 3 * 10^ {- 6}m to be stretched, the tungsten will stretch 0.25 of that ratio

L_T = 3*10^{-6}*0.25

L_T = 7.5*10^{-7}m

Therefore the amount of stretch of Tungsten is 7.5*10^{-7}m

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3. In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 100 m/s collides with a 1.50-kg cart (Cart B) movin
Alex787 [66]

Answer:

The speed of the two carts after the collision is 10 m/s.

Explanation:

Hi there!

The momentum of the system Cart A - Cart B is conserved because there is no external force acting on the system at the instant of the collision. Then, the momentum of the system before the collision will be equal to the momentum of the system after the collision. The momentum of the system is calculated as the sum of momenta of cart A and cart B:

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2

Solving for vAB2:

(mA · vA1 + mB · vB1) / (mA + mB) = vAB2

(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2

vAB2 = 10 m/s

The speed of the two carts after the collision is 10 m/s.

6 0
3 years ago
Look at the graph below. Which elements together make up seven percent of the Earth’s crust? calcium and iron calcium and sodium
yaroslaw [1]
The graph is missing, however we can answer anyway.

In fact, this is the approximate percentage of the elements listed in the questions in the Earth's crust (data taken from wikipedia):
Iron 5.0 %
Calcium 3.6 %
Sodium 2.8 %
Potassium 2.6 %
Magnesium 1.5 %

of all of these, we see that the combination of two elements that makes up the closest number to 7% is calcium and sodium (3.6% + 2.8%=6.4%), therefore the correct answer is
Calcium and sodium.
4 0
2 years ago
A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 90.0 m above the
romanna [79]

Answer:

d = 771.3m

Explanation:

Let's first calculate the time of flight:

Yf = Yo+Voy*t-g*t^2/2  where Voy=0. Solving for t:

t = \sqrt{2*90/9.8} =4.285s

Now we calculate the horizontal displacement, wihch is the distance from the target to drop the package:

Xf = d = Vox*t

d = 180*4.285 = 771.3m

6 0
3 years ago
An automobile fuel tank is filled to the brim with 45 L of gasoline (12 gal) at 10°C. Immediately afterward, the vehicle is park
spayn [35]

Answer:

10.7L of gasoline overflows

Explanation:

See attached file

7 0
3 years ago
A building that is 105.50 ft. feet tall is casting a shadow that is 37.50 ft. feet. If the building next to it, is casting a sha
Arlecino [84]
115.35 ft

Set the proportion up 37.50/105.50 = 41/x and solve for x
7 0
3 years ago
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