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4 years ago

4x + 2y = 8? what is the graph to this

Mathematics

2 answers:

deff fn [24]4 years ago

8 0

2y=8-4x
Divide everything by 2
Y=4-2x
Go up 4 on the y axis and plot
From that point, go up 2 and to the right 1.

atroni [7]4 years ago

7 0

Y= -2x+4
The graph is linear

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Schach [20]

G’(x)=0
Explaination

Take the derivative of both sides

Subtract the numbers

4 0

4 years ago

At the store for every 2 movies sold there 8 books sold. What is the radio of books sold to movies sold?

Leto [7]

Answer:

The ratio of books sold to movies sold at the store is 4:1.

Step-by-step explanation:

Given that:

Number of movies sold at the store = 2 movies

Number of books sold at the store = 8 books

Ratio of books sold to movies sold at the store is

Books sold : Movies sold

8 : 2

$\frac{8}{2}:\frac{2}{2}$

4 : 1

Hence,

The ratio of books sold to movies sold at the store is 4:1.

5 0

3 years ago

Please help me out .

nexus9112 [7]

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3 0

3 years ago

Can someone help me out please ?

givi [52]

Answer:

2 + r = 7

Step-by-step explanation:

To write an equation for the image, simply look on both sides and add everything together. On the left side we have seven 1's, which adds up to 7. On the right side, we have 2 1's, which add up to 2, and a variable r. Now, we do not know the value of the variable r, so we simply leave it be. Therefore, the right side is equal to 2 + r. Since the image represents a balanced equation, the left side must equal the right side.

Left side = 7

Right side = 2 + r

Left side = Right side

7 = 2 + r

2 + r = 7

4 0

3 years ago

Read 2 more answers

Show that

madam [21]

Answer:

See below

Step-by-step explanation:

Use same power to compare the values

Prove the first part:

$\sqrt[3]{3}+\sqrt{2} >\sqrt[3]{9}$
$\sqrt[6]{3^2}+\sqrt[6]{2^3} >\sqrt[6]{9^2}$
$\sqrt[6]{9}+\sqrt[6]{8} >\sqrt[6]{81}$
$\sqrt[6]{9}+\sqrt[6]{8}> \sqrt[6]{8}+\sqrt[6]{8}=2\sqrt[6]{8}=\sqrt[6]{8*64} =\sqrt[6]{512} >\sqrt[6]{81}$
$512 > 81$

Prove the second part:

$\sqrt[3]{9} >\sqrt[4]{13}$
$\sqrt[12]{9^4} >\sqrt[12]{13^3}$
$\sqrt[12]{6561} >\sqrt[12]{2197}$
$6561 > 2197$

3 0

2 years ago