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Mamont248 [21]
3 years ago
5

CHEMISTRY HELP PLEASE!!!

Chemistry
2 answers:
Viefleur [7K]3 years ago
6 0

Answer : when a beaker of acid is titrated with a basic solution, the acid becomes neutralized.

Explanation :

The reaction in which an acid reacts with a base forming a salt and water is known as neutralization reaction.

During neutralization reaction, acid and base neutralize each other.

That means they both lose their properties and completely new substances are formed which have different properties

For example, a reaction of acid HCl with base NaOH produces water and salt, NaCl.

HCl + NaOH \rightarrow NaCl + H2O

Therefore we can say that, when a beaker of acid is titrated with a basic solution, the acid is neutralized.

rewona [7]3 years ago
5 0
The acid becomes neutralised.
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Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B
Ivenika [448]

Answer:

-2546 kJ

Explanation:

It is possible to obtain the enthalpy of a reaction from the sum of different intermediate reactions.

For the reaction:

4B(s) + 3O₂(g) → 2B₂O₃(s)

The intermediate reactions are:

A- B₂O₃(s) + 3H₂O(g) → 3O₂(g) + B₂H₆(g), ΔH°A= +2035 kJ

B- 2B(s) + 3H₂(g) → B₂H₆(g), ΔH°B= +36 kJ

C- H₂(g) + 1/2O₂(g) → H₂O(l), ΔH°C= -285 kJ

D- H₂O(l) → H₂O(g), ΔH°D= +44 kJ

2B = 4B(s) + 6H₂(g) → 2B₂H₆(g) ΔH°2B= +78 kJ

-2A = 6O₂(g) + 2B₂H₆(g) → 2B₂O₃(s) + 6H₂O(g) ΔH°-2A= -4070 kJ

-6C = 6H₂O(l) → 6H₂(g) + 3O₂(g) ΔH°-6C= +1710 kJ

-6D = 6H₂O(g) → 6H₂O(l) ΔH°-6D = -264 kJ

The sum of 2B - 2A - 6C - 6D produce:

4B(s) + 3O₂(g) → 2B₂O₃(s)

And the enthalpy is: ΔH°2B + ΔH°-2A + ΔH°-6C + ΔH°-6D = <em>-2546 kJ</em>

I hope it helps!

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Answer: Ion-ion forces, also known as ionic bonding, are the simplest to understand. These forces arise from the electrostatic attraction between two ions with opposite charges.

Explanation:

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