All categories

3 years ago

CHEMISTRY HELP PLEASE!!!

Chemistry

2 answers:

Viefleur [7K]3 years ago

6 0

Answer : when a beaker of acid is titrated with a basic solution, the acid becomes neutralized.

Explanation :

The reaction in which an acid reacts with a base forming a salt and water is known as neutralization reaction.

During neutralization reaction, acid and base neutralize each other.

That means they both lose their properties and completely new substances are formed which have different properties

For example, a reaction of acid HCl with base NaOH produces water and salt, NaCl.

$HCl + NaOH \rightarrow NaCl + H2O$

Therefore we can say that, when a beaker of acid is titrated with a basic solution, the acid is neutralized.

rewona [7]3 years ago

5 0

The acid becomes neutralised.

You might be interested in

The heat of vaporization Δ1, of toluene (C6H5CH3) is 38.1 kJ/mol. Calculate the change in entropy AS when 207. g of toluene boil

AveGali [126]

Answer: The change in entropy change when 207 g of toluene boils at $110.6^{o}C$ is 223 $J/K$ .

Explanation:

It is given that mass of toulene is 207 g and its molar mass is 92.14 g/mol. So, its moles will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{207 g}{92.14 g/mol}$

= 2.25 moles

As we are given that heat of vaporization for 1 mol is 38.1 kJ/mol. So, heat of vaporization for 2.25 moles will be calculated as follows.

$2.25 moles \times 38.1 KJ/mol$

= 85.725 KJ

Now, we know that the relation between enthalpy change and entropy change is as follows.

$\Delta S = \frac{\Delta H}{\Delta T}$

= $\frac{85.725 kJ}{(110.6 + 273) K}$

= 0.223 $kJ/K$

or, = 223 $J/K$ (as 1 kJ = 1000 J)

Thus, we can conclude that the change in entropy change when 207 g of toluene boils at $110.6^{o}C$ is 223 $J/K$ .

7 0

4 years ago

The nonvolatile, nonelectrolyte DDT, C14H9Cl5 (354.50 g/mol), is soluble in diethyl ether CH3CH2OCH2CH3. Calculate the osmotic p

aleksandrvk [35]

Answer:

2.50 atm

Explanation:

We have 10.4 g of DDT (solute), whose molar mass is 354.50 g/mol. The corresponding moles are:

10.4 g × (1 mol/354.50 g) = 0.0293 mol

The molarity of the solution is:

M = moles of solute / liters of solution

M = 0.0293 mol / 0.286 L

M = 0.102 M

We can find the osmotic pressure (π) using the following pressure.

π = M × R × T

where,

R: ideal gas constant

T: absolute temperature

π = M × R × T

π = 0.102 M × 0.0821 atm.L/mol.K × 298 K

π = 2.50 atm

5 0

3 years ago

What is the passage from the mouth to the larynx and esophagus?

Paladinen [302]

The answer is the trachea

6 0

4 years ago

Parents should avoid sharing their own mistakes with children. True/false

Vesna [10]

Parents SHOULDN'T avoid sharing their own mistakes with children.

6 0

3 years ago

Read 2 more answers

2 A certain gas of 25 g at 25°c and 0.65 atm occupies a volume of 23.52L Determine the molecule mass of the gas.

denpristay [2]

Answer:

${ \bf{PV= \frac{m}{M} RT}} \\ \\ { \tt{(0.65 \times 23.52) = \frac{25}{M} \times 0.081 \times (25 + 273)}} \\ \\ M = 39.5 \: g$

8 0

3 years ago