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KiRa [710]
3 years ago
11

Which unit of measure is used to indicate Ecell?

Chemistry
2 answers:
OlgaM077 [116]3 years ago
8 0

<u>Answer:</u> Volts is the unit used to measure cell potential.

<u>Explanation:</u>

Units is defined as the standard which is used to make comparisons between the measurements.

<u>For Example:</u> Meter is the unit used to measure length, Liters is the unit used to measure volume etc...

E_{cell} is defined as the EMF of the cell. It is the energy provided by a cell per coulomb of charge that passes through it. It is measured with the unit of Volts (V).

Hence, volts is the unit used to measure cell potential.

insens350 [35]3 years ago
7 0
V is used to indicate Ecell ( just look at what measurement is simplified to V) <span />
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Determine the number of hydrogen atoms in the following compound 3Cu(C2H3O2)2
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Answer:5

Explanation:(H3) is 3 (H3)2 is 5

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How do muscles work in pairs to make parts of the body move?
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Muscles work in pairs to move a bone.

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Explain in terms of particle behavior why smoke particles cause the detector alarm to sound


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Compare and contrast the burning of wood and the metabolism of glucose in your cells. How are they similar, and how are they dif
Alisiya [41]

Burning of wood is a combustion reaction and the metabolism of glucose in your cells is cellular respiratory reaction.

Cellular respiration releases stored energy in glucose molecules and converts it into a form of energy that can be used by cells.

Cellular respiration is the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water.

Wood as well as many common items that combust are organic (i.e., they are made up of carbon, hydrogen and oxygen). When organic molecules combust the reaction products are carbon dioxide and water (as well as heat)

Similarities:

1. Combustion reaction and metabolism of glucose both require oxygen.

2. Combustion and metabolism of glucose both product carbon dioxide and water

3. Both produces by-products: After cellular respiration and combustion have gotten what they needed from the wood, there will be byproducts from the conversion. In the case of combustion, they are noxious gases like carbon monoxide. In the case of respiration, the sugar molecule is broken into two molecules of pyruvic acid.

4. Catalyst: While breaking apart the bonds to release the stored energy either combustion or sugars for respiration the bonds will not broken by themselves. In each case, a catalyst is required to start the reaction that will break the bonds apart. In the case of combustion, the catalyst is a spark. Wood are flammable, so the spark will ignite the burning, breaking apart the bonds and releasing the energy. For respiration, enzymes are used to break the sugar molecule apart.

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2. Glucose metabolism is an endothermic reaction while combustion is an exothermic reaction (produces heat)

8 0
3 years ago
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
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