That thing is used as a lever.
The coefficient of friction between the Tyre and the ground is 0.11
<u>Explanation:</u>
Given:
Radius of the track (r)=125 m.
Speed with which the car travels (v) =42 km/hr
=11.67 m/s
To Find:
Coefficient of friction between the Tyre and the ground.
Formula to be used:
We know that,Frictional force is equal to centripetal force
Frictional force=μmg
therefore 1.08 m=μmg
Cancelling "m" on both sides we get,
μ=1.08/g=1.08/9.8
=0.11
Thus the coefficient of friction between the Tyre and the ground is 0.11
Answer:
Because of the frequency off the wave I think
Explanation:
Answer:
4117.65 N
Explanation:
Speed of ball, u = 126 km/h = 35 m/s
Mass of ball, m = 160 g = 0.16 kg
Time interval, t = 1.36 ms = 0.00136 s
We can calculate the force as a measure of the momentum of the ball:
F = P/t
Momentum, P, is given as:
P = mv
Therefore:
F = (mv) / t
F = (0.16 * 35) / (0.00136)
F = 4117.65 N
The force imparted to the two glove d hands of the inexperienced catcher is 4117.65 N.