Answer:
2.5
Explanation:
The capacitance of a parallel-plate capacitor filled with dielectric is given by
where
k is the dielectric constant
is the capacitance of the capacitor without dielectric
In this problem,
is the capacitance of the capacitor in air
is the capacitance with the dielectric inserted
Solving the equation for k, we find
Answer:
The answer is
<h2>84.9 kPa</h2>
Explanation:
Using Boyle's law to find the final pressure
That's
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the final pressure
From the question
P1 = 115 kPa
V1 = 480 mL
V2 = 650 ml
So we have
We have the final answer as
<h3>84.9 kPa</h3>
Hope this helps you
<h2>
Answer:</h2>
Abraham
<h2>
Explanation:</h2>
This story can be found in the bible, in Genesis 22. According to the story, the Lord tested Abraham's faith asking him to sacrifice Isaac his son in a mountain in the land of Moriah. Abraham traveled with his son three days until he found the place the Lord has established for the sacrifice. There, Abraham tied his son and laid him on the altar on top of a wood he had prepared. Abraham picked up a knife to kill his son as a sacrifice but the Lord called him from heaven saying: <em>"Do not hurt him in any way, for now I know that you truly fear God. You have not withheld from me even your son, your only son"</em>
Answer:
By a factor of 1/4.
Explanation:
The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,
in which 
, 
represent the change in momentum and the time taken for that change.
If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by 
, the following manipulation confirms the answer to this question.
![\begin{aligned}\\\small F_1 &=\small \frac{\Delta (mV)}{4\Delta t}\\\\&=\small \frac{1}{4}\times\bigg[\frac{\Delta (mV)}{\Delta t}\bigg]\\\\&=\small \frac{1}{4}F\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5C%5C%5Csmall%20F_1%20%26%3D%5Csmall%20%5Cfrac%7B%5CDelta%20%28mV%29%7D%7B4%5CDelta%20t%7D%5C%5C%5C%5C%26%3D%5Csmall%20%5Cfrac%7B1%7D%7B4%7D%5Ctimes%5Cbigg%5B%5Cfrac%7B%5CDelta%20%28mV%29%7D%7B%5CDelta%20t%7D%5Cbigg%5D%5C%5C%5C%5C%26%3D%5Csmall%20%5Cfrac%7B1%7D%7B4%7DF%5Cend%7Baligned%7D)
Here 
is the force that was applied to the object previously.
#SPJ4
<span>This reduction happens because potential energy transforms to "thermal energy" and "sound energy"
Hope this helps!</span>
