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3 years ago

How is a solute different from a solvent in a solution?

2 answers:

6 0

A solute is the substance that is being dissolved into a solvent. The solvent is the liquid that the solute is being dissolved into.

Example: When you have CoolAid, the powder thing is the solute and the water is the solvent. The powder is being dissolved into the water to give it the color.

kotegsom [21]3 years ago

5 0

A solution is basically two substances that are mixed together.. A solute is the substance to be dissolved (sugar). The solvent is the one doing the dissolving (water) Hoped i helped :D

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What does lower case k stand for?

DaniilM [7]

Just for more clarification, lowercase k is the rate constant. Uppercase K is the equilibrium constant. You can actually use k to find K (equilibrium constant). K=k/k' This means that the equilibrium constant is the rate constant of the forward reaction divided by the rate constant of the reverse reaction

4 0

4 years ago

In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i

GalinKa [24]

Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: $V_{1}$ = 21.35 mL, $M_{1}$ = 0.150 M

$V_{2}$ = 25.0 mL, $M_{2}$ = ?

Formula used to calculate molarity of $H_{2}SO_{4}$ is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M$

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = $V_{1} + V_{2}$

= 21.35 mL + 25.0 mL

= 46.36 mL (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol$

Thus, we can conclude that there are 0.006 moles of acid in the flask.

3 0

3 years ago

What are chemistry questions for high school students about atomic size trends?

serg [7]

It is mostly about an element, it usually goes like this: "which element has the bigger atomic size, Sodium or Oxygen? "

8 0

3 years ago

a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minu

lutik1710 [3]

The compound formed is the quaternary ammonium salt N,N,N-trimethyl-1-phenylmethanaminium iodide.

Quaternary ammonium salts are formed when methyl iodide reacts with an amine. The quaternary ammonium salt is an ionic substance which often has a high melting point. Remember that the melting point of a substance can be used to identify the substance.

In this case, a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minutes of reaction, a white precipitate formed. the precipitate was isolated and its melting point was recorded to be 178 °c. This precipitate must be N,N,N-trimethyl-1-phenylmethanaminium iodide (Benzyltrimethylammonium iodide) because it is a quaternary ammonium salt whose melting point is 178 °c.

Learn more: brainly.com/question/5325004

8 0

2 years ago

A saline solution contains 1.6 % NaCl by mass.How much NaCl is present in 57.2 g of this solution?

nekit [7.7K]

Answer:

0.92 g

Explanation:

Given data:

Percentage of NaCl = 1.6%

Amount of NaCl present in 57.2 g = ?

Solution:

1.6% of 57.2 g NaCl:

1.6/100× 57.2 g

0.92 g

So in 57.2 g 1.6% of NaCl is 0.92 g.

6 0

3 years ago