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kvasek [131]
3 years ago
12

Question 4, can you give me the rule for naming these?

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
3 0

3 ethyl, 4 methylheptane. The compound is named by first identifying the longest carbon chain in the structure. in this case the chain has seven carbon atoms thus the prefix hept-.

Next you identify the substituent groups attached to the long carbon chain and name them from the lowest value of the integer assigned to the carbon atoms from either side. From the right, the ethyl group is attached to carbon number 3 while from the left, the methyl group is attached to carbon number 4. We therefore start with the right and name the attached groups first, including the carbon atoms to which they are attached.

Then we also take into consideration the highest number of bonds between the carbon atoms which is one from the question. Thus the suffix -ane is added if a maximum of one bond, -ene,if two bonds and -yne if three bonds.

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answer: B
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3 years ago
An unknown compound does not dissolve in water, is a nonelectrolyte and has a low melting point. Would it be an ionic compound?
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No, it's not an ionic compound.
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3 years ago
When the sun hits the water the water...
wolverine [178]

Answer:

It creates a rainbow

Explanation:

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5 0
3 years ago
A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. The molecular weight of the unkn
Pie

Answer: 128 g/mol

Explanation:

Graham's law states that  the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.

Mathematically, that is:

\frac{Rate_1}{Rate_2}=\sqrt{\frac{MolarMass_2}{MolarMass_1} }

Since, you know the ratio of two rates and the molar mass of one gas, you can calculate the molar mass of the other gas.

The molar mass of the oxygen molecule, O₂ = 2×16.0g/mol = 32.0 g/mol.

In the coming equations, I will use 32 g/mol for simplicity of writing.

\frac{Rate_1}{Rate_2}=2 \\ \\ \\ MolarMass_1=32g/mol\\\\\\ 2=\sqrt{\frac{MolarMass_2}{32g/mol} } \\ \\ \\ 4=\frac{MolarMass_2}{32g/mol}\\ \\ \\ MolarMass_2=128g/mol

So, the molecular mass of the unnknown gas is 128 g/mol.

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3 years ago
How do you increase the concentration of a solution wiki?
never [62]
It would be to change the amount of solute or solvent in the solution.
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3 years ago
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