No, it's not an ionic compound.
The distinguishing properties of ionic compounds are that they dissolve in water (water's polarity pulls the ions apart), are electrolytes (dissociate into ions, which conduct electricity), and have high melting points (it takes a lot of energy to separate the ions without water or other polar compounds). Since the unknown compound has the opposite of all these properties, it's not ionic.
Answer:
It creates a rainbow
Explanation:
Cause of the reflectiveness of the water it could possibly form another light but more colorful. you can see how it works when its becomes summer, get a water hose and just let it flow. you'll see a miniature rainbow.
Answer: 128 g/mol
Explanation:
Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.
Mathematically, that is:

Since, you know the ratio of two rates and the molar mass of one gas, you can calculate the molar mass of the other gas.
The molar mass of the oxygen molecule, O₂ = 2×16.0g/mol = 32.0 g/mol.
In the coming equations, I will use 32 g/mol for simplicity of writing.

So, the molecular mass of the unnknown gas is 128 g/mol.
It would be to change the amount of solute or solvent in the solution.