Answer:
Coal is a traditionally used source of energy, there are main four types of ranks for coal. Here the rank of a coal means to a natural process called Coalification, which takes place during a plant is buried and changes to a harder, and denser material and become even more rich in carbon contents.
Anthracite is know to have the highest ranked coal, it contains highest percent of fixed carbon and lowest percent of volatile material.
Answer:
True
Explanation:
When a theory is proven over and over it will become a law
<span> The formula for </span>measuring<span> density is Density = </span>Mass/Volume<span>, or D=M/V. The / means “per” or “for each,” which in math is the same as “divided by.”</span>
So first find the volume
so 7.78g/ml and (3.7505 times 10^4) grams
therefor we dividde (3.7505 times 10^4) by 7.78 and get how many ml
the answer is 4820.69 ml
kL means kilo lieters
kilo=1000
kL=1000Liters
ml=milileters=1/1000 leiter
1000ml=1L
therfor
1kL=1000L
1000L=1000 times (1000ml)
1000L=1,000,000ml
1kL=1,000,000ml
so to convert to kL divide 4820.69 by 1,000,000
0.00482069
convert to scientifiic notation
4.8 times 10^-3
the answer is 4.8 times 10^-3 kL
<u>Answer:</u> The empirical formula for the given compound is 
<u>Explanation:</u>
We are given:
Percentage of H = 5.80 %
Percentage of O = 23.02 %
Percentage of N = 20.16 %
Percentage of Cl = 51.02 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of H = 5.80 g
Mass of O = 23.02 g
Mass of N = 20.16 g
Mass of Cl = 51.02 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Hydrogen = 
Moles of Oxygen = 
Moles of Nitrogen = 
Moles of Chlorine = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.
For Hydrogen = 
For Oxygen = 
For Nitrogen = 
For Chlorine = 
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of H : O : N : Cl = 4 : 1 : 1 : 1
Hence, the empirical formula for the given compound is 