Question

Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

Answer 1

The weight of the load is (mass) x (gravity).

The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance)

The power is (work)/(time) =

               (mass) x (gravity) x (distance) / (time)  = 

               (500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =

                (500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =

                 (500 x 9.8 x 12 / 1)    newton  -  meter / sec =

                  (500 x 9.8 x 12 / 1)             joule        /  sec =

                                 58,800    watts

                         =       58.8 kW

                         =      about  78.8 horsepower