Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

1 answer:

8 0

The weight of the load is (mass) x (gravity).

The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance)

The power is (work)/(time) =

   (mass) x (gravity) x (distance) / (time) =

   (500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =

(500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =

   (500 x 9.8 x 12 / 1) newton - meter / sec =

(500 x 9.8 x 12 / 1) joule    / sec =

   58,800 watts

   = <em>58.8 kW</em>

   =    about 78.8 horsepower

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<h3>What is mechanical advantage?</h3>

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It is used to obtain the efficiency of forces in levers and pulleys. It is an effective way of amplifying the force in simple machines like levers.

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