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Anestetic [448]
3 years ago
15

Chemical energy stored in food cannot be transformed into mechanical energy true or false

Physics
1 answer:
Orlov [11]3 years ago
5 0
If that statement were true, then you would never have any reason to eat.
It might taste good for a while, but it would never help you stand up and
move around.

Where WOULD you get the energy to stand up and walk, if it didn't
come from food ? ?

The whole idea is pretty absurd.  I guess the statement is not true.
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Which do you think will penetrate farther into a block of lead, x-rays, or gamma rays
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Gamma rays because it has more penetrating power and frequency but shorter wavelength.
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the brakes on a car do 240000j of work in stopping the car. if the car travels a distance of 40m while the brakes re being appli
Tpy6a [65]
A joule is one Newton of force applied over a meter.
For every meter, the brakes put 240000N of force (N=Newtons).
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3 0
3 years ago
Sam, whose mass is 78 kg , stands at the top of a 11-m-high, 110-m-long snow-covered slope. His skis have a coefficient of kinet
Valentin [98]

Answer:

v = 8.09   m/s

Explanation:

For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.

Let's calculate the energy

       

starting point. Higher

         Em₀ = U = m gh

final point. To go down the slope

         Em_f = K = ½ m v²

The work of the friction force is

         W = fr L cos 180

to find the friction force let's use Newton's second law

Axis y

        N - W_y = 0

        N = W_y

X axis

        Wₓ - fr = ma

let's use trigonometry

        sin  θ = y / L

         sin θ = 11/110 = 0.1

         θ = sin⁻¹  0.1

          θ = 5.74º

         sin 5.74 = Wₓ / W

         cos 5.74 = W_y / W

         Wₓ = W sin 5.74

         W_y = W cos 5.74

the formula for the friction force is

         fr = μ N

         fr = μ W cos θ

Work is friction force is

         W_fr = - μ W L cos θ  

Let's use the relationship of work with energy

        W + ΔU = ΔK

         -μ mg L cos 5.74 + (mgh - 0) = 0  - ½ m v²

        v² = - 2 μ g L cos 5.74 +2 (gh)

        v² = 2gh - 2 μ gL cos 5.74

let's calculate

        v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74

        v² = 215.6 -150.16

        v = √65.44

        v = 8.09   m/s

6 0
3 years ago
What type of energy transformation occurs when a light bulb is turned on?
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Electical energy is transformed into heat and light energy
4 0
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