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svet-max [94.6K]
4 years ago
11

Which statement accurately describes a balanced force?

Physics
1 answer:
Yuki888 [10]4 years ago
5 0

Answer:

a balanced force is when two forces equal each other out and therefor the object is not in motion.

Explanation:

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How much time should be allowed for a 605-mile car trip if the car will be traveling at an average speed of 55 miles per hour?
lesya692 [45]
To find how long it will take for the trip divide miles by the speed.

605 / 55 = 11

So it will take 11 hours to get to the destination.
4 0
4 years ago
Read 2 more answers
Um automóvel percorre 6,0 km para o norte e, em seguida 8,0 km para o leste. A intensidade do vetor posição, em relação ao ponto
Valentin [98]

Answer:

Explanation:

A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km

Check attachment for diagram

The intensity of the position vector is equal to the displacement,

So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.

So, applying Pythagorean theorem

c² = a² + b²

R² = 6² + 36²

R² = 36 + 64

R² = 100

R = √100

R = 10 km.

Verifique el adjunto para ver el diagrama

La intensidad del vector de posición es igual al desplazamiento,

Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.

Entonces, aplicando el teorema de Pitágoras

c² = a² + b²

R² = 6² + 36²

R² = 36 + 64

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7 0
3 years ago
A block of mass 0.490 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T
Dennis_Churaev [7]

Answer:

The value of x is  x = 0.1955\ m

The value of the velocity at the top is  v_{top} = 2.25 \ m/s

Explanation:

The diagram of this process is on the first uploaded image

From the question we are told that

     The mass of the block is m_b = 0.490kg

      The distance of compression is x

      The force constant is k = 450 N/m

      The radius of the circular track is R =1.00m

       The speed at the bottom of the track is v_A = 13.4 \ m/s

        The frictional force experienced is F_f = 7.00 \ N

Now looking at this process we see that the potential energy of the spring is been transformed into the kinetic energy  of the block . So,

          PE \ of \ spring = KE \ of  \ block

mathematically i.e

        \frac{1}{2}k x^2  = \frac{1}{2} m_bv^2_A

       0.5 * 450 * x^2 = 0.5 * 0.490 * 13.4^2

Making x the subject of the formula

           x = \sqrt{\frac{0.5 * 0.490 * 13.4^2}{ 0.5 * 450} }

              = 0.1955\ m

The average workdone by friction is  W_f = F_f * \pi

Here \pi is \ the\  net\ displacement

                                         W_f = 7 * 3.142

                                               = 21.99 J

The kinetic energy at the bottom is

                                     KE = \frac{1}{2} * 0.490 * 13.4^2

                                            = 43.99 \ N

The potential energy gained at the top of the circle is

                              PE = m_bgh

Here h  is the height which is equal to d(diameter)  = 2r = 2 × 1 = 2 m and

g is acceleration due to gravity = 9.8m/s^2

Now substituting values

                       PE = 0.490 * 9.8 *2

                             =9.604 J

Since energy is can not be created nor destroyed but transformed  according to first law of thermodynamics

                  KE_{at \bottom} = PE _ {\ at \ top } + W_f + KE_{\ at \ top}

                      43.99 = 9.604 +21.99 + [\frac{1}{2} m_b * v_{top} ^2]

                        12.369= [2.45* v_{top} ^2]

                            v_{top} =\sqrt{\frac{12.369}{2.45} }

                                  = 2.25 \ m/s

                                     

                                 

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