Answer:
d = 229.5 m
Explanation:
It is given that,
Total mass of a ski-plane is 1200 kg
It lands towards the west on a frozen lake at 30.0 m/s.
The coefficient of kinetic friction between the skis and the ice is 0.200.
We need to find the distance covered by the plane before coming to rest. In this case,
It is decelerating, a = -1.96 m/s²
Now using the third equation of motion to find the distance covered by the plane such that :
So, the plane slide a distance of 229.5 m.
Answer:
<u> Power = 9.75 ×10^8</u>
Explanation:
For one second 650m^3 of water flows out down to 150m oh depth.
So, the energy at a height of 150m is transformed to kinetic energy.
for a second,
650m^3 of water flows down ⇒ (1000kg/m^3 × 650m^3) = 6.5×10^5kg of warer flos down.
The total gravitational potential energy stored in water is
= <u>mass of water × height× gravity</u>
= 6.5 ×10^5 × 150 × 10 = 9.75 ×10^8
As it is transformed in a second it is also equal to <u>Power.</u>