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Tatiana [17]
4 years ago
15

HELP!!! please if anyone could help me with these two questions.?

Chemistry
2 answers:
Zina [86]4 years ago
5 0

Answer:

(Question 5) examine and describe cells

Explanation:

The microscope was only made to view cells/materials up close. Not any of those other answers....

IRINA_888 [86]4 years ago
3 0
The answers are D and B I just did the same thing like 20 mins ago trust me! Your welcome!
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Which of the following is a phenotype?<br> A. Aa<br> B. Black hair<br> C. DNA<br> or D. Heterozygous
Rudiy27
The answer is C. DNA
7 0
3 years ago
Plzzzz Help!!!!
Alona [7]
Explanation:
In order to calculate the molarity of a solution, you need to know two things
the number of moles of solute present in solution
the total volume of the solution
The problem provides you with a
24.7-g
sample of potassium chloride,
KCl
, and a total volume of a solution of
500. mL
.
In order to find the number of moles of potassium chloride, your solute, use the compound's molar mass, which as you know tells you the mass of one mole of potassium chloride
5 0
3 years ago
Which is a difference between animal populations in primary succession and secondary succession?
Sindrei [870]

Answer:

this may help

Explanation:

in primary succession, newly exposed or newly formed rock is colonized by living things for the first time. In secondary succession, an area that was previously occupied by living things is disturbed, then re-colonized following the disturbance.

4 0
3 years ago
Read 2 more answers
If the mass of 293nv is 293.10 amu and that of 295nv is 295.45 amu , what is the atomic weight of nv?
ycow [4]

Answer;

294.13 amu

Solution;

-293nv is 293.10 amu and that of 295nv is 295.45 amu

293.05+295.2=588.25

588.25/2= 294.13 amu

an amu of 294.13 using significant figures

3 0
4 years ago
Write a net ionic equation for the reaction of hydrochloric acid with ammonia in aqueous solution. And write a net ionic equatio
zavuch27 [327]

Explanation:

(a)  When aqueous solution of hydrochloric and ammonia chemically react together then it results in the formation of ammonium chloride.

The reaction equation for this reaction is as follows.

          HCl(aq) + NH_{3}(aq) \rightarrow NH_{4}Cl(aq)

Now, ioni equation for this reaction is as follows.

     H^{+}(aq) + Cl^{-}(aq) + NH_{3}(aq) \rightarrow NH_{4}^{+}(aq) + Cl^{-}(aq)

Cancelling the spectator ions, the net ionic reaction equation is as follows.

       H^{+}(aq) + NH_{3}(aq) \rightarrow NH^{+}_{4}(aq)    

(b)   When sodium hydroxide chemically reacts with ammonium chloride then it forms ammonia, water and sodium chloride as follows.

     NaOH(aq) + NH_{4}Cl(aq) \rightarrow NH_{3}(aq) + NaCl(aq) + H_{2}O(l)

Now, the total ionic equation will be as follows.

  Na^{+}(aq) + OH^{-}(aq) + NH^{+}_{4}(aq) + Cl^{-}(aq) \rightarrow NH_{3}(aq) + Na^{+}(aq) + Cl^{-}(aq) + H_{2}O(l)

Cancelling the spectator ions from the above equation. Then the net ionic equation will be as follows.

        OH^{-}(aq) + NH^{+}_{4}(aq) \rightarrow NH_{3}(aq) + H_{2}O(l)  

6 0
4 years ago
Read 2 more answers
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