Answer:
This atomic model has changed over time. Scientists used the model to make predictions. Sometimes the results of their experiments were a surprise and they did not fit with the existing model. Scientists changed the model so that it could explain the new evidence.
Explanation:
Answer:
they are use to make tar, asphalt, paraffin wax, and lubricating oils.
Explanation:
Answer:
The statement true is A. A and B are isotopes of the same element.
Explanation:
Isotopes correspond to atoms of the same element with different mass numbers (A), that is to say they differ in the amount of neutrons in the nucleus. In the case of compound A it has 10 neutrons, and B has 11.
The metric prefixes which is not one multiple of ten when moving forward or backward between prefixes is: none of the above
Option c is the correct answer
<h3>What is metric prefix?</h3>
A metric prefix simply refers to a unit prefix that precedes a basic unit of measure to indicate a multiple or sub-multiple of the unit.
So therefore, the metric prefixes which is not one multiple of ten when moving forward or backward between prefixes is: none of the above
Complete question:
Which of the following metric prefixes are not one multiple of ten when moving forward or backward between prefixes?
a. micro
b.nano
c. none of the above
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Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P× V = n× R× T
In this case, you know:
- P= 2 atm
- V= ?
- n=
being 2g/mole the molar mass of H2, that is, the amount of mass that a substance contains in one mole. - R= 0.082
- T= 353 K
Replacing:
2 atm× V = 4.745 moles× 0.082× 353 K
Solving:
V = (4.745 moles× 0.082× 353 K)÷ 2 atm
<u><em>V= 68.67 L</em></u>
Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
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