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maks197457 [2]
3 years ago
8

Write a net ionic equation for the reaction of hydrochloric acid with ammonia in aqueous solution. And write a net ionic equatio

n for the reaction Sodium hydroxide (aq) + ammonium chloride (aq).
Chemistry
2 answers:
zavuch27 [327]3 years ago
6 0

Explanation:

(a)  When aqueous solution of hydrochloric and ammonia chemically react together then it results in the formation of ammonium chloride.

The reaction equation for this reaction is as follows.

          HCl(aq) + NH_{3}(aq) \rightarrow NH_{4}Cl(aq)

Now, ioni equation for this reaction is as follows.

     H^{+}(aq) + Cl^{-}(aq) + NH_{3}(aq) \rightarrow NH_{4}^{+}(aq) + Cl^{-}(aq)

Cancelling the spectator ions, the net ionic reaction equation is as follows.

       H^{+}(aq) + NH_{3}(aq) \rightarrow NH^{+}_{4}(aq)    

(b)   When sodium hydroxide chemically reacts with ammonium chloride then it forms ammonia, water and sodium chloride as follows.

     NaOH(aq) + NH_{4}Cl(aq) \rightarrow NH_{3}(aq) + NaCl(aq) + H_{2}O(l)

Now, the total ionic equation will be as follows.

  Na^{+}(aq) + OH^{-}(aq) + NH^{+}_{4}(aq) + Cl^{-}(aq) \rightarrow NH_{3}(aq) + Na^{+}(aq) + Cl^{-}(aq) + H_{2}O(l)

Cancelling the spectator ions from the above equation. Then the net ionic equation will be as follows.

        OH^{-}(aq) + NH^{+}_{4}(aq) \rightarrow NH_{3}(aq) + H_{2}O(l)  

Yanka [14]3 years ago
5 0

Answer:

<em>(a)  When aqueous solution of hydrochloric and ammonia chemically react together then it results in the formation of ammonium chloride.</em>

<em />

<em>The reaction equation for this reaction is as follows.</em>

<em />

<em>          </em>

<em />

<em>Now, ioni equation for this reaction is as follows.</em>

<em />

<em>     </em>

<em />

<em>Cancelling the spectator ions, the net ionic reaction equation is as follows.</em>

<em />

<em>           </em>

<em />

<em />

<em>(b)   When sodium hydroxide chemically reacts with ammonium chloride then it forms ammonia, water and sodium chloride as follows.</em>

<em />

<em>     </em>

<em />

<em>Now, the total ionic equation will be as follows.</em>

<em />

<em>  </em>

<em />

<em>Cancelling the spectator ions from the above equation. Then the net ionic equation will be as follows.</em>

 

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